Solve -x/-(-y): Double Negative Fraction with Values 4 and 1/3

Let's start with the first option.

Let's substitute the numbers in the given expression:

$\frac{-4}{-(-(-\frac{1}{3})}=$

Let's remember the rule:

$-(-x)=+x$

Therefore:

$\frac{-4}{-(+\frac{1}{3})}=$

Let's remember the rule:

$-(+x)=-x$

Now the exercise we got is:

$\frac{-4}{-\frac{1}{3}}=$

Note that we are dividing between two negative numbers, so the result must be a positive number:

$\frac{-}{-}=+$

$\frac{4}{\frac{1}{3}}=$

Let's convert the division to multiplication and remember to switch between the numerator and denominator of the simple fraction:

$4\times\frac{3}{1}=\frac{12}{1}=12$

Let's move on to solve the second option.

Let's substitute the numbers in the given expression:

$\frac{-(-4)}{-(-(+\frac{1}{3})}=$

Let's remember the rules:

$-(-x)=+x$

$-(+x)=-x$

Now we get:

$\frac{+4}{-(-\frac{1}{3})}=\frac{+4}{+\frac{1}{3}}=$

Note that we are dividing between two positive numbers, so the result must be a positive number:

$\frac{+}{+}=+$

Let's convert the division to multiplication and remember to switch between the numerator and denominator of the simple fraction:

$4\times\frac{3}{1}=\frac{12}{1}=12$

The final answer is:

$1,2=+12$