Subtract 19 from 48 Using Base-10 Blocks: Visual Mathematics

To solve the problem of finding how many blocks remain after removing 19 from 48, we will perform the subtraction operation and handle regrouping if necessary:

Step 1: Start with the original number of blocks: $48$.

Step 2: We need to subtract 19 from this total. Let's write this subtraction vertically:

$\begin{array}{c} 48 \\ - 19 \\ \hline \end{array}$

Step 3: In the units column (rightmost column), we have 8 (from 48) and we need to subtract 9. Since 8 is smaller than 9, we regroup from the tens column. This leaves us with:

• Convert one 10 from the tens place in 48, leaving 3 tens, and add that 10 to the units column, making it 18.
• Now subtract 9 from 18 in the units column. This results in 9.

Step 4: Proceed to the tens column. We regrouped once, so we're left with 3 tens (from original 4 tens). Subtract 1 ten (from the 19) from 3 tens, leaving us with 2 tens.

Thus, the remaining amount after performing the subtraction is:

$\begin{array}{c} 3 & 8 \\ - 1 & 9 \\ \hline 2 & 9 \\ \end{array}$

Therefore, the number of blocks remaining is $\boxed{29}$.