Uncover the Decreasing Pattern: 12,000,000, 11,000,000, ...

Arithmetic Sequences with Million-Unit Decreases

Complete the sequence:

12,000,000, 11,000,000,  12{,}000{,}000,\ 11{,}000{,}000, \ \ldots

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Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Complete the sequence:

12,000,000, 11,000,000,  12{,}000{,}000,\ 11{,}000{,}000, \ \ldots

2

Step-by-step solution

To solve this problem, we need to determine the pattern of the given number sequence:

  • Step 1: Identify the pattern in the sequence. The sequence begins with 12,000,00012{,}000{,}000 followed by 11,000,00011{,}000{,}000.
  • Step 2: Calculate the difference between the two given terms. The difference is 12,000,00011,000,000=1,000,00012{,}000{,}000 - 11{,}000{,}000 = 1{,}000{,}000.
  • Step 3: This indicates a consistent decrease by 1,000,0001{,}000{,}000 between consecutive terms.
  • Step 4: To find the next number after 11,000,00011{,}000{,}000, subtract 1,000,0001{,}000{,}000, yielding 10,000,00010{,}000{,}000.
  • Step 5: Continue applying this pattern:
    • The number after 10,000,00010{,}000{,}000 is 10,000,0001,000,000=9,000,00010{,}000{,}000 - 1{,}000{,}000 = 9{,}000{,}000.
    • Finally, the number after 9,000,0009{,}000{,}000 is 9,000,0001,000,000=8,000,0009{,}000{,}000 - 1{,}000{,}000 = 8{,}000{,}000.

Hence, the next numbers in the sequence are 10,000,00010{,}000{,}000, 9,000,0009{,}000{,}000, and 8,000,0008{,}000{,}000.

Therefore, the correct continuation of the sequence is 10,000,000, 9,000,000, 8,000,00010{,}000{,}000,\ 9{,}000{,}000,\ 8{,}000{,}000.

3

Final Answer

10,000,000, 9,000,000, 8,000,000 10{,}000{,}000,\ 9{,}000{,}000, \ 8{,}000{,}000

Key Points to Remember

Essential concepts to master this topic
  • Pattern Recognition: Each term decreases by exactly one million
  • Technique: Calculate difference: 12,000,00011,000,000=1,000,000 12{,}000{,}000 - 11{,}000{,}000 = 1{,}000{,}000
  • Check: Verify pattern holds for all terms: consistent 1,000,000 -1{,}000{,}000 difference ✓

Common Mistakes

Avoid these frequent errors
  • Adding instead of subtracting the common difference
    Don't add 1,000,000 to continue the pattern = 12,000,000, 13,000,000! This creates an increasing sequence when the numbers are clearly getting smaller. Always identify whether the sequence increases or decreases first, then apply the correct operation.

Practice Quiz

Test your knowledge with interactive questions

Complete the sequence:

\( 20{,}000,\ 20{,}001,\ 20{,}002, \ \ldots \)

FAQ

Everything you need to know about this question

How do I know if the sequence is increasing or decreasing?

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Look at the first two terms! Since 12,000,000>11,000,000 12{,}000{,}000 > 11{,}000{,}000 , the sequence is decreasing. Each term gets smaller by the same amount.

What if the numbers don't decrease by round millions?

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The same method works! Find the difference between consecutive terms. For example, if you had 12,500,000 then 11,200,000, the difference would be 1,300,000.

How many terms should I find in the sequence?

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Usually the problem tells you! Look for phrases like "find the next three terms" or count how many blanks need to be filled in the answer choices.

Can arithmetic sequences have negative numbers?

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Absolutely! If this sequence continued long enough, you'd eventually get to 0, then -1,000,000, -2,000,000, etc. The pattern stays the same!

What's the fastest way to find the 10th term?

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Use the formula: nth term = first term + (n-1) × common difference. For the 10th term: 12,000,000+(101)×(1,000,000)=3,000,000 12{,}000{,}000 + (10-1) × (-1{,}000{,}000) = 3{,}000{,}000 .

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