Associative Property: By multiplication only

According to the order of operations, we must solve the exercise from left to right.

But, this can leave us with awkward or complicated numbers to calculate.

Since the entire exercise is a multiplication, you can use the associative property to reorganize the exercise:

3*5*4=

We will start by calculating the second exercise, so we will mark it with parentheses:

3*(5*4)=

3*(20)=

Now, we can easily solve the rest of the exercise:

3*20=60

According to the rules of the order of operations, you can use the substitution property and start the exercise from right to left to comfortably calculate:

$5\times2=10$

$7\times10=70$

According to the rules of the order of operations, we solve the exercise from left to right:

$12\times5=60$

$60\times6=360$

Since we only have a multiplication operation in the exercise, we can solve the easier part first (the right-hand side):

$4\times25=100$

Now we get:

$27\times100=$

This exercise is simple and doesn't require much calculation. Since we are multiplying by 100, the only operation we need to add is two zeros to 27:

$2,700$

According to the order of operations rules, since the exercise only involves multiplication, we can solve it from right to left:

$5\times2=10$

Now we will get the exercise:

$18\times10=$

Since this is a multiplication exercise with a round number ending in 0, we won't need to calculate at all, but simply add the 0 to the result we got before.

Therefore we will get the number:

$180$

According to the order of operations rules, since the exercise has only multiplication, we will solve it from left to right:

$15\times2=30$

Now we will get the exercise:

$30\times9=$

We will calculate the exercise by putting aside the tens of the number 30 and solve the exercise:

$3\times9=27$

Now we can add the tens that we previously set aside, and add them to the result we got.

This way we will get the number:

$270$

According to the order of operations rules, since the exercise has only multiplication, we can solve it from right to left, as this is the simpler exercise:

$10\times10=100$

Now we will get the exercise:

$102\times100=$

Since this is a multiplication exercise where we multiply by 100, without calculation we can simply take the two zeros of the 100 and add them to the result we got in the previous exercise.

It's important to make sure to write the decimal point in the correct place.

Now we will get the number:

$10,200$

According to the order of operations rules, given that the exercise is only comprised of multiplication, we can solve it from right to left, as this is the simpler way:

$2\times5=10$

We should obtain the following:

$19\times10=$

Given that this is a multiplication exercise where we multiply by 10, without calculating we can simply take the zero from the 10 and write it after the number 19.

Resulting in the following:

$190$

According to the rules of the order of operations, you can use the substitution property and organize the exercise in a more convenient way to calculate:

$35\times2\times6=$

We solve the exercise from left to right:

$35\times2=70$

$70\times2=140$

According to the order of operations rules, since the exercise has only multiplication operations, we will solve the exercise from left to right.

We will solve the left exercise in the following way, by breaking down 102 into a smaller addition exercise:

$(100+2)\times11=$

Now we'll multiply 11 by each of the numbers in parentheses:

$(100\times11)+(2\times11)=$

We'll solve each of the exercises in parentheses and get:

$1,100+22=1,122$

Now we'll get the exercise:

$1,122\times10=$

Since this is a multiplication exercise with a round number ending in 0, we can solve the exercise without calculation by adding a 0 to the number 1,122

It's important to place the comma in the appropriate place, and we'll get the number:

$11,220$

According to the order of operations, we must solve the problem from left to right since the exercise involves only multiplication.

$20\times6=120$

Hence:

$120\times3=360$

According to the order of operations rules, since the exercise only has multiplication, we will solve the exercise from left to right.

We will solve the left exercise in vertical multiplication format to make the solving process easier for ourselves.

It's important to maintain the correct order of solving, meaning first multiply the ones digit of the first number by the ones digit of the second number,
then multiply the tens digit of the first number by the ones digit of the second number, and so on.

$35\\\times3\\=105$

Now we will get the exercise:

$105\times24=$

We will solve this exercise vertically as well, following the same rules as we did in the previous exercise.

$105\\\times24\\=2,520$

Upon observing the exercise note that we have two "regular" numbers and one number with a variable.
Given that this is a multiplication exercise, multiplying a number with a variable by a number without a variable doesn't present a problem.

In fact, it's important to remember that a variable attached to a number represents multiplication itself, for example in this case: $11\times x$
Therefore, we can apply the distributive property to separate the variable, and come back to it later.
Proceed to solve the exercise from right to left since it's simpler this way.

$5\times6=30$

We obtain the following:

$11x\times30=$

We'll put aside the x and add it at the end of the exercise.

By solving the exercise in an organized way we simplify the solution process.

It's important to maintain the correct order when solving the problem, meaning first multiply the ones of the first number by the ones of the second number,
then the tens of the first number by the ones of the second number, and so on.

$30\\\times11\\=330$

Don't forget to add the variable at the end. The answer is as follows:

$330x$

Upon observing the exercise note that we have two "regular" numbers and one number with a variable.
Given that this is a multiplication exercise, multiplying a number with a variable by a number without a variable doesn't present a problem.

In fact, it's important to remember that a variable attached to a number represents multiplication by itself, for example in this case: $2\times x$
Therefore, we can apply the distributive property in order to separate the variable, and come back to it later.
Solve the exercise from left to right.

Solve the left exercise by breaking down the decimal number into an addition problem of a whole number and a decimal number as follows:

$2\times(4+0.65)=$

Multiply 2 by each term inside of parentheses:

$(2\times4)+(2\times0.65)=$

Solve each of the expressions inside of the parentheses as follows:

$8+1.3=9.3$

We obtain the following exercise:

$9.3\times6.3=$

Solve the exercise vertically in order to simplify the solution process.

It's important to be careful with the proper placement of the exercise, using the decimal point as an anchor.
Then we can proceed to multiply in order, first the ones digit of the first number by the ones digit of the second number. Then the tens digit of the first number by the ones digit of the second number, and so on.

$9.3\\\times6.3\\=58.59$

Don't forget to add the variable at the end resulting in the following answer:

$58.59x$

Upon observing the exercise note that we have two "regular" numbers and one number with a variable.
Given that this is a multiplication exercise, multiplying a number with a variable by a number without a variable doesn't present a problem.

In fact, it's important to remember that a variable attached to a number represents multiplication by itself, for example in this case: $5.2\times x$
Therefore, we can apply the distributive property in order to separate the variable, and come back to it later.
Proceed to solve the exercise from left to right.

Solve the left exercise vertically in order to avoid confusion as shown below:

$~~~~~15.6 \\\times~~~~5.2 \\=~81.12$

It's important to be careful with the correct placement of the exercise, where the decimal point serves as an anchor.
Then we can multiply in order, first the ones digit of the first number by the ones digit of the second number.
Next the tens digit of the first number by the ones digit of the second number, and so on.

We should obtain the following:

$81.21\times0.3=$

Remember that:

$0.3=\text{0}.30$

Calculate:

$24.336$

Let's not forget to add the variable at the end resulting in the following answer:

$24.336 x$

First, let's convert all mixed fractions to simple fractions:

$\frac{3\times6+5}{6}\times\frac{5\times6+5}{6}\times\frac{1}{3}x=$

Let's solve the exercises with the eight fractions:

$\frac{18+5}{6}\times\frac{30+5}{6}\times\frac{1}{3}x=$

$\frac{23}{6}\times\frac{35}{6}\times\frac{1}{3}x=$

Since the exercise only involves multiplication, we'll combine all the numerators and denominators:

$\frac{23\times35}{6\times6\times3}x=\frac{805}{108}x$