Examples with solutions for Types of Triangles: Using variables

Exercise #1

Below is an equilateral triangle:

XXX

If the perimeter of the triangle is 33 cm, then what is the value of X?

Video Solution

Step-by-Step Solution

We know that in an equilateral triangle all sides are equal.

Therefore, if we know that one side is equal to X, then all sides are equal to X.

We know that the perimeter of the triangle is 33.

The perimeter of the triangle is equal to the sum of the sides together.

We replace the data:

x+x+x=33 x+x+x=33

3x=33 3x=33

We divide the two sections by 3:

3x3=333 \frac{3x}{3}=\frac{33}{3}

x=11 x=11

Answer

11

Exercise #2

Look at the following triangle:

2X2X2X3.5X3.5X3.5X3X3X3X

The perimeter of the triangle is 17.

What is the value of X?

Video Solution

Step-by-Step Solution

We know that the perimeter of a triangle is equal to the sum of all sides together, so we replace the data:

3x+2x+3.5x=17 3x+2x+3.5x=17

8.5x=17 8.5x=17

Divide the two sections by 8.5:

8.5x8.5=178.5 \frac{8.5x}{8.5}=\frac{17}{8.5}

x=2 x=2

Answer

2

Exercise #3

Triangle ABC is a right triangle.

The area of the triangle is 6 cm².

Calculate X and the length of the side BC.

S=6S=6S=6444X-1X-1X-1X+1X+1X+1AAACCCBBB

Video Solution

Step-by-Step Solution

We use the formula to calculate the area of the right triangle:

ACBC2=cateto×cateto2 \frac{AC\cdot BC}{2}=\frac{cateto\times cateto}{2}

And compare the expression with the area of the triangle 6 6

4(X1)2=6 \frac{4\cdot(X-1)}{2}=6

Multiplying the equation by the common denominator means that we multiply by 2 2

4(X1)=12 4(X-1)=12

We distribute the parentheses before the distributive property

4X4=12 4X-4=12 / +4 +4

4X=16 4X=16 / :4 :4

X=4 X=4

We replace X=4 X=4 in the expression BC BC and

find:

BC=X1=41=3 BC=X-1=4-1=3

Answer

X=4, BC=3