Multiplication and division: 4 Numbers

1. Follow the order of operations (PEMDAS/BODMAS).

2. First do the division: $6 \div 2 = 3$.

3. Then, perform the addition/subtraction from left to right: $9 - 3 = 6$, then $6 + 3 = 9$.

1. Follow the order of operations (PEMDAS/BODMAS).

2. First do the division: $8 \div 4 = 2$.

3. Then, perform the multiplication: $3 \times 3 = 9$.

4. Finally, perform the addition: $2 + 9 = 11$.

1. Follow the order of operations (PEMDAS/BODMAS).

2. First do the division: $9 \div 3 = 3$.

3. Then, perform the multiplication: $5 \times 2 = 10$.

4. Finally, perform the addition: $10 + 3 = 13$.

1. Follow the order of operations (PEMDAS/BODMAS).

2. First do the multiplication: $2 \times 5 = 10$.

3. Then, perform the addition: $6 + 10 = 16$.

4. Finally, subtract: $16 - 4 = 12$.

According to the order of operations, we place the multiplication and division exercise within parentheses:

$(20:4)+(3\times2)=$

Now we solve the exercises within parentheses:

$20:4=5$

$3\times2=6$

And we obtain the exercise:

$5+6=11$

According to the order of operations, we put the multiplication and division exercise in parentheses:

$(15:5)+(4\times3)=$

Now we solve the parentheses:

$15:5=3$

$4\times3=12$

And we get the exercise:

$3+12=15$

According to the rules of the order of arithmetic operations, we begin by enclosing the multiplication exercise inside parentheses:

$2-(5\times3)+4=$

We then solve the said exercise inside of the parentheses:

$5\times3=15$

We obtain the following:

$2-15+4=$

Lastly we solve the exercise from left to right:

$2-15=-13$

$-13+4=-9$

According to the rules of the order of arithmetic operations, we must first solve the multiplication exercises.

We place them inside of parentheses to avoid confusion during the solution:

$4-(5\times7)+3=$

We then solve the multiplication exercises:

$4-35+3=$

Lastly we solve the rest of the exercise from left to right:

$4-35=-31$

$-31+3=-28$

According to the rules of the order of operations, we first place multiplication and division exercises within parentheses:

$10-(4:2\times2)=$

We solve the exercise within parentheses from left to right:

$4:2=2$

$2\times2=4$

Now we obtain the exercise:

$10-4=6$

According to the rules of the order of operations, we first solve the multiplication exercise:

$3+8+(4\times3)=$

$4\times3=12$

Now, we solve the addition exercise from left to right:

$3+8+12=$

$11+12=23$

According to the rules of the order of operations we should first solve the exercise from left to right since it only contains a division operation:

$80:4=20$

$20:2=10$

$10:5=2$

First, perform the multiplication: $3 \times 2 = 6$.

Then, follow the sequence with addition: $8 + 6 = 14$.

Finally, perform the subtraction: $14 - 5 = 9$.

Multiply first: $7 \times 2 = 14$.

Subtract 3: $14 - 3 = 11$.

Add 1: $11 + 1 = 12$.

Perform the multiplication first: $4 \times 1 = 4$.

Then, subtract the result from 9: $9 - 4 = 5$.

Finally, add 2: $5 + 2 = 7$.

Start by performing the multiplication and division from left to right according to the order of operations.

First, calculate the multiplication: $2 \times 5 = 10$

Next, divide the result by 1: $10 \div 1 = 10$

Finally, multiply by 4: $10 \times 4 = 40$

Thus, the correct answer is $40$.

Start by performing the multiplication and division from left to right according to the order of operations.

First, calculate the multiplication: $6 \times 3 = 18$

Next, divide the result by 2: $18 \div 2 = 9$

Finally, multiply by 1: $9 \times 1 = 9$

Thus, the correct answer is $9$.

Start with the multiplication: $4 \times 2 = 8$.

Add this to the initial subtraction: $11 - 2 = 9$.

Then finish with: $9 + 8 = 17$.

To solve the expression $8 \div 2 \times 3 \times 2$, we need to follow the order of operations, specifically multiplication and division from left to right.

First, we divide 8 by 2:

$8 \div 2 = 4$

Next, we multiply the result by 3:

$4 \times 3 = 12$

Finally, we multiply by 2:

$12 \times 2 = 24$

Thus, the value of $8 \div 2 \times 3 \times 2$ is $24$.

According to the order of operations, we first put the multiplication exercise in parentheses to avoid confusion in the rest of the solution:

$(25\times6)-9-41=$

Let's solve the multiplication exercise first:

$150-9-41=$

Now let's solve the exercise from left to right:

$150-9=141$

$141-41=100$

First, perform the division: $48 \div 8 = 6$.

Next, perform the multiplication: $6 \times 3 = 18$.

Finally, perform the addition: $16 + 18 = 34$.