Multiplication and division: Addition, subtraction, multiplication and division

To solve $8 \div 2 \times 4$, you need to follow the order of operations: first perform the division and then the multiplication.

Step 1: Divide 8 by 2: $8 \div 2 = 4$

Step 2: Multiply the result by 4: $4 \times 4 = 16$

So, the answer is $16$.

According to the rules of the order of operations, the exercise which contains both multiplication and division should be solved from left to right.

$30:5=6$

$6\times2=12$

According to the rules of the order of arithmetic operations, we must first solve the multiplication exercises.

We place them inside of parentheses to avoid confusion during the solution:

$4-(5\times7)+3=$

We then solve the multiplication exercises:

$4-35+3=$

Lastly we solve the rest of the exercise from left to right:

$4-35=-31$

$-31+3=-28$

According to the rules of the order of operations, we first place multiplication and division exercises within parentheses:

$10-(4:2\times2)=$

We solve the exercise within parentheses from left to right:

$4:2=2$

$2\times2=4$

Now we obtain the exercise:

$10-4=6$

According to the order of operations, we put the multiplication and division exercise in parentheses:

$(15:5)+(4\times3)=$

Now we solve the parentheses:

$15:5=3$

$4\times3=12$

And we get the exercise:

$3+12=15$

According to the order of operations, we place the multiplication and division exercise within parentheses:

$(20:4)+(3\times2)=$

Now we solve the exercises within parentheses:

$20:4=5$

$3\times2=6$

And we obtain the exercise:

$5+6=11$

According to the rules of the order of arithmetic operations, we begin by enclosing the multiplication exercise inside parentheses:

$2-(5\times3)+4=$

We then solve the said exercise inside of the parentheses:

$5\times3=15$

We obtain the following:

$2-15+4=$

Lastly we solve the exercise from left to right:

$2-15=-13$

$-13+4=-9$

According to the rules of the order of operations, we first solve the multiplication exercise:

$3+8+(4\times3)=$

$4\times3=12$

Now, we solve the addition exercise from left to right:

$3+8+12=$

$11+12=23$

According to the order of operations, we first put the multiplication exercise in parentheses to avoid confusion in the rest of the solution:

$(25\times6)-9-41=$

Let's solve the multiplication exercise first:

$150-9-41=$

Now let's solve the exercise from left to right:

$150-9=141$

$141-41=100$

According to the rules of the order of arithmetic operations, we must first place multiplication and division exercises inside of parentheses:

$2+3-(15:3\times4)+6=$

We then solve the exercise within the parentheses from left to right:

$15:3=5$

$5\times4=20$

After which we are left with the following exercise:

$2+3-20+6=$

Lastly we solve the exercise from left to right:

$2+3=5$

$5-20=-15$

$-15+6=-9$

According to the rules of the order of arithmetic operations, we must first solve the multiplication exercises.

We place them inside of parentheses in order to avoid confusion during the solution:

$2+(3\times6)-(3\times7)+1=$

We then solve the multiplication exercises:

$2+18-21+1=$

Lastly we solve the rest of the exercise from left to right:

$2+18=20$

$20-21=-1$

$-1+1=0$

According to the rules of the order of arithmetic operations, we must first place the multiplication and division exercises within parentheses:

$2-(6:2)+(5\times2)=$

We then solve the exercise inside of the parentheses:

$6:2=3$

$5\times2=10$

We obtain the following exercise:

$2-3+10=$

Finally we solve the exercise from left to right:

$2-3=-1$

$-1+10=9$

According to the rules of the order of arithmetic operations, we must first place the multiplication and division exercises within parentheses:

$(4\times7\times2:4)-(1\times9)=$

We then proceed to solve the exercise in parentheses from left to right:

$4\times7=28$

$28\times2=56$

$56:4=14$

We obtain the following exercise:

$14-9=5$

According to the rules of the order of arithmetic operations, we must first place the multiplication and division exercises within parentheses:

$5-(30:2\times3)+10=$

We then solve the exercise inside of the parentheses from left to right:

$30:2=15$

$15\times3=45$

We obtain the following exercise:

$5-45+10=$

Finally we solve the exercise from left to right:

$5-45=-40$

$-40+10=-30$

According to the rules of the order of arithmetic operations, we must first place multiplication and division exercises within parentheses:

$7+(3\times7)-(3\times4)+5=$

We then proceed to solve the exercise inside of the parentheses:

$3\times7=21$

$3\times4=12$

We obtain the following exercise:

$7+21-12+5=$

Lastly we solve the exercise from left to right:

$21+7=28$

$28-12=16$

$16+5=21$

According to the rules of the order of arithmetic operations, we begin by placing the multiplication and division exercises inside of parentheses:

$8+(3\times4)-2+1=$

We then solve the exercise within the parentheses:

$3\times4=12$

We obtain the following :

$8+12-2+1=$

Finally we solve the exercise from left to right:

$8+12=20$

$20-2=18$

$18+1=19$

According to the order of operations rules, we first insert the multiplication and division exercises into parentheses:

$3+(4:2\times1)-9+4=$

We'll solve the exercise from left to right:

$4:2=2$

$2\times1=2$

And we'll obtain the following exercise:

$3+2-9+4=$

Since the exercise only contains subtraction operations, we'll solve it from left to right:

$3+2=5$

$5-9=-4$

$-4+4=0$

According to the order of operations rules, we first insert the multiplication and division exercises into parentheses:

$(24:2)-4-(3:3)=$

Let's solve the exercises in parentheses:

$24:2=12$

$3:3=1$

Now we have the expression:

$12-4-1=$

Let's solve the expression from left to right:

$12-4=8$

$8-1=7$

According to the order of operations rules, we first enter the multiplication and division exercises into parentheses:

$(5\times5\times2)-(12:4)=$

Now let's solve the exercises in parentheses from left to right:

$5\times5=25$

$25\times2=50$

$12:4=3$

We obtain the following exercise:

$50-3=47$

According to the order of operations, we will first solve the multiplication exercises.

We will put them in parentheses so that we don't get confused later in the solution:

$25-(3\times4)+(4\times2)=$

Let's solve the multiplication exercises:

$3\times4=12$

$4\times2=8$

We get:

$25-12+8=$

Let's solve the exercise from left to right:

$25-12=13$

$13+8=21$