Multiplication and division: Addition, subtraction, multiplication and division

According to the rules of the order of operations, the exercise which contains both multiplication and division should be solved from left to right.

$30:5=6$

$6\times2=12$

To solve $8 \div 2 \times 4$, you need to follow the order of operations: first perform the division and then the multiplication.

Step 1: Divide 8 by 2: $8 \div 2 = 4$

Step 2: Multiply the result by 4: $4 \times 4 = 16$

So, the answer is $16$.

According to the order of operations, we place the multiplication and division exercise within parentheses:

$(20:4)+(3\times2)=$

Now we solve the exercises within parentheses:

$20:4=5$

$3\times2=6$

And we obtain the exercise:

$5+6=11$

According to the order of operations, we put the multiplication and division exercise in parentheses:

$(15:5)+(4\times3)=$

Now we solve the parentheses:

$15:5=3$

$4\times3=12$

And we get the exercise:

$3+12=15$

According to the rules of the order of arithmetic operations, we begin by enclosing the multiplication exercise inside parentheses:

$2-(5\times3)+4=$

We then solve the said exercise inside of the parentheses:

$5\times3=15$

We obtain the following:

$2-15+4=$

Lastly we solve the exercise from left to right:

$2-15=-13$

$-13+4=-9$

According to the rules of the order of arithmetic operations, we must first solve the multiplication exercises.

We place them inside of parentheses to avoid confusion during the solution:

$4-(5\times7)+3=$

We then solve the multiplication exercises:

$4-35+3=$

Lastly we solve the rest of the exercise from left to right:

$4-35=-31$

$-31+3=-28$

According to the rules of the order of operations, we first place multiplication and division exercises within parentheses:

$10-(4:2\times2)=$

We solve the exercise within parentheses from left to right:

$4:2=2$

$2\times2=4$

Now we obtain the exercise:

$10-4=6$

According to the rules of the order of operations, we first solve the multiplication exercise:

$3+8+(4\times3)=$

$4\times3=12$

Now, we solve the addition exercise from left to right:

$3+8+12=$

$11+12=23$

According to the order of operations, we first put the multiplication exercise in parentheses to avoid confusion in the rest of the solution:

$(25\times6)-9-41=$

Let's solve the multiplication exercise first:

$150-9-41=$

Now let's solve the exercise from left to right:

$150-9=141$

$141-41=100$

According to the order of arithmetic operations, multiplication and division precede addition and subtraction,

Therefore, let's start first with the division operation:

$3+10-(2:4)+1=3+10-\frac{1}{2}+1$

Now, as all remaining operations are at the same level (addition and subtraction),

let's start solving from left to right:

$3+10-\frac{1}{2}+1=13-\frac{1}{2}+1$

$13-\frac{1}{2}+1=12\frac{1}{2}+1=13\frac{1}{2}$

According to the order of operations rules, we first enter the multiplication and division exercises into parentheses:

$(5\times5\times2)-(12:4)=$

Now let's solve the exercises in parentheses from left to right:

$5\times5=25$

$25\times2=50$

$12:4=3$

We obtain the following exercise:

$50-3=47$

According to the order of operations rules, we first insert the multiplication and division exercises into parentheses:

$(24:2)-4-(3:3)=$

Let's solve the exercises in parentheses:

$24:2=12$

$3:3=1$

Now we have the expression:

$12-4-1=$

Let's solve the expression from left to right:

$12-4=8$

$8-1=7$

According to the order of operations rules, we first insert the multiplication and division exercises into parentheses:

$2+(4\times5:2)+3=$

Now let's solve the expression in parentheses from left to right:

$4\times5=20$

$20:2=10$

And we get the expression:

$2+10+3=$

Let's solve the expression from left to right:

$2+10=12$

$12+3=15$

According to the order of operations rules, we first insert the multiplication and division exercises into parentheses:

$3+(4:2\times1)-9+4=$

We'll solve the exercise from left to right:

$4:2=2$

$2\times1=2$

And we'll obtain the following exercise:

$3+2-9+4=$

Since the exercise only contains subtraction operations, we'll solve it from left to right:

$3+2=5$

$5-9=-4$

$-4+4=0$

According to the order of operations, we place the multiplication and division exercise in parentheses:

$(12:4)-3+(3\times3)=$

We solve the exercises in parentheses:

$12:4=3$

$3\times3=9$

And we obtain the exercise:

$3-3+9=$

According to the order of operations, we solve the exercise from left to right:

$3-3=0$

$0+9=9$

According to the order of operations, we place the multiplication and division exercise within parentheses:

$(9:3)-(1.5\times2)=$

Now we solve the exercises within parentheses:

$9:3=3$

$1.5\times2=3$

And we obtain the exercise:

$3-3=0$

According to the order of operations, we will first solve the multiplication exercises.

We will put them in parentheses so that we don't get confused later in the solution:

$25-(3\times4)+(4\times2)=$

Let's solve the multiplication exercises:

$3\times4=12$

$4\times2=8$

We get:

$25-12+8=$

Let's solve the exercise from left to right:

$25-12=13$

$13+8=21$

According to the rules of the order of arithmetic operations, we begin by placing the multiplication and division exercises inside of parentheses:

$8+(3\times4)-2+1=$

We then solve the exercise within the parentheses:

$3\times4=12$

We obtain the following :

$8+12-2+1=$

Finally we solve the exercise from left to right:

$8+12=20$

$20-2=18$

$18+1=19$

According to the rules of the order of arithmetic operations, we must first enclose both the multiplication and division exercises inside of parentheses:

$1+(2\times3)-(7:4)=$

We then solve the exercises within the parentheses:

$2\times3=6$

$7:4=\frac{7}{4}$

We obtain the following:

$1+6-\frac{7}{4}=$

We continue by solving the exercise from left to right:

$1+6=7$

$7-\frac{7}{4}=$

Lastly we break down the numerator of the fraction with a sum exercise as seen below:

$7-(\frac{4+3}{4})$

$7-(\frac{4}{4}+\frac{3}{4})$

$7-(1+\frac{3}{4})$

$7-1\frac{3}{4}=5\frac{1}{4}$

According to the rules of the order of arithmetic operations, we must first place multiplication and division exercises inside of parentheses:

$2+3-(15:3\times4)+6=$

We then solve the exercise within the parentheses from left to right:

$15:3=5$

$5\times4=20$

After which we are left with the following exercise:

$2+3-20+6=$

Lastly we solve the exercise from left to right:

$2+3=5$

$5-20=-15$

$-15+6=-9$