4-Digit Number Pattern: Finding Numbers with Equal Tens and Thousands Digits Below 2200

To solve this problem, we should carefully examine each of the provided choices, ensuring they meet all necessary criteria:

• The number should be a 4-digit number.
• The tens digit should be equal to the thousands digit.
• The number should be less than 2200.

Let's analyze each option:

1. $2220$:
Thousands digit = 2, Tens digit = 2 (Condition satisfied that they are equal)
However, the number is greater than 2200.

2. $2002$:
Thousands digit = 2, Tens digit = 0 (Condition not satisfied as digits are different)
The number itself is less than 2200.

3. $2020$:
Thousands digit = 2, Tens digit = 2 (Condition satisfied that they are equal)
The number is less than 2200.

4. $2222$:
Thousands digit = 2, Tens digit = 2 (Condition satisfied that they are equal)
The number is greater than 2200.

From this breakdown, the number that satisfies both necessary conditions is $2020$.

Thus, the correct answer is $2020$.