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To solve this problem, we'll follow these steps:
Units place addition:
We place in the units place and carry over to the tens place.
, plus the carried over :
We place in the tens place and carry over to the hundreds place.
, plus the carried over :
Place in the hundreds place and carry over to the next place, creating a new thousands place digit.
Resulting sum:
Therefore, the solution to the problem is .
1000
\( \begin{aligned} &83 \\ +& \\ &~~6 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
When digits add up to 10 or more, you write the ones digit in that column and carry the tens digit to the next column left. It's like trading 10 ones for 1 ten!
We start from the units place (rightmost) because any carrying affects the column to the left. If we started left, we'd have to redo our work when carries happen!
That's completely normal! In 822 + 178, we carry three times. Just handle one column at a time: add the digits, add any carry from the right, then carry left if needed.
Try adding the numbers in reverse order: 178 + 822. You should get the same answer. Or subtract one original number from your sum to get the other original number!
When the leftmost column needs to carry (like ), you create a new thousands place. That's why 822 + 178 becomes the 4-digit number 1000!
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