Luciana's age is 3 times Ivana's age.
Hector is 10 years younger than Luciana.
The sum of the three ages is 32.
How old is Hector?
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Luciana's age is 3 times Ivana's age.
Hector is 10 years younger than Luciana.
The sum of the three ages is 32.
How old is Hector?
To solve this problem, let's define the variables and set up the equation:
We know the sum of their ages is 32, so we set up the equation:
Simplify the equation:
Next, solve for :
Add 10 to both sides:
Divide both sides by 7:
Now that we know Ivana is 6 years old, we can find Hector's age:
Hector's age =
Therefore, Hector is 8 years old.
\( x+7=14 \)
\( x=\text{?} \)
Choose the person that others are compared to. Since Luciana is "3 times Ivana's age" and Hector is compared to Luciana, make Ivana's age = x. This keeps your expressions simple!
If Luciana is years old, then someone 10 years younger is . Remember: younger means subtract, older means add!
Check your setup! Negative ages usually mean you set up the relationships backwards. Make sure "younger than" uses subtraction and "older than" uses addition.
Verify two things: (1) All ages are positive, and (2) The relationships work. Here: Ivana = 6, Luciana = 18 (which is 3×6 ✓), Hector = 8 (which is 18-10 ✓).
In the equation , we have three x-terms: x + 3x + 3x = 7x. Always collect all x-terms together before solving!
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