Area Calculation: Finding Total Surface Area of 3/8 and 1/4 Fractions in 10,000m²

The area of a field is 10,000 square meters.

On 38 \frac{3}{8} of the land, there is a banana plantation and on14 \frac{1}{4} of there land there is a watermelon plantation.

What is the total surface area covered by the banana and watermelon plantations?

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1

Understand the problem

The area of a field is 10,000 square meters.

On 38 \frac{3}{8} of the land, there is a banana plantation and on14 \frac{1}{4} of there land there is a watermelon plantation.

What is the total surface area covered by the banana and watermelon plantations?

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the area covered by the banana plantation.

  • Step 2: Identify the area covered by the watermelon plantation.

  • Step 3: Sum the two areas to find the total area covered by both plantations.

Now, let's work through each step:
Step 1: The banana plantation covers 38\frac{3}{8} of the field.
Calculate its area: 10,000×38=10,000×0.375=3,750m210,000 \times \frac{3}{8} = 10,000 \times 0.375 = 3,750 \, \text{m}^2.

Step 2: The watermelon plantation covers 14\frac{1}{4} of the field.
Calculate its area: 10,000×14=10,000×0.25=2,500m210,000 \times \frac{1}{4} = 10,000 \times 0.25 = 2,500 \, \text{m}^2.

Step 3: Add these areas to find the total area covered by both plantations:
3,750m2+2,500m2=6,250m23,750 \, \text{m}^2 + 2,500 \, \text{m}^2 = 6,250 \, \text{m}^2.

Therefore, the total surface area covered by the banana and watermelon plantations is 6,250m2 \text{m}^2 .

3

Final Answer

6,250²

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\( \)\( \frac{4}{5}+\frac{1}{5}= \)

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