Break Down the Algebraic Expression: 3y³ into Basic Terms

Algebraic Expressions with Exponential Decomposition

Break down the expression into basic terms:

3y3 3y^3

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Step-by-step written solution

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1

Understand the problem

Break down the expression into basic terms:

3y3 3y^3

2

Step-by-step solution

To break down the expression 3y3 3y^3 into its basic terms, we understand the components of the expression:

3is a constant multiplier 3 \, \text{is a constant multiplier}

y3 y^3 can be rewritten as yyy y \cdot y \cdot y

Thus, 3y3 3y^3 can be decomposed into 3yyy 3 \cdot y \cdot y \cdot y .

3

Final Answer

3yyy 3\cdot y\cdot y \cdot y

Key Points to Remember

Essential concepts to master this topic
  • Definition: Breaking down means writing each factor separately and explicitly
  • Technique: Rewrite y3 y^3 as yyy y \cdot y \cdot y to show repeated multiplication
  • Check: Count factors: 3 has one factor, y appears three times ✓

Common Mistakes

Avoid these frequent errors
  • Applying exponent to coefficient
    Don't write 33y3 3^3 \cdot y^3 = 27y³! The exponent 3 only applies to the variable y, not the coefficient 3. Always keep the coefficient separate and only expand the exponential part.

Practice Quiz

Test your knowledge with interactive questions

Break down the expression into basic terms:

\( 4x^2 + 6x \)

FAQ

Everything you need to know about this question

Why don't I write the 3 as 3¹?

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While technically 3 = 3¹, we don't usually write the exponent 1 because it's understood. The goal is to break down into basic terms, so 3 stays as just 3.

What does 'basic terms' actually mean?

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Basic terms means showing every single factor separately using multiplication. Instead of shortcuts like exponents, we write out yyy y \cdot y \cdot y to see exactly what we're multiplying.

Is there a difference between 3y³ and y³ × 3?

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No difference at all! Due to the commutative property of multiplication, 3y3=y33 3y^3 = y^3 \cdot 3 . Both equal 3yyy 3 \cdot y \cdot y \cdot y when broken down.

How do I know when I've broken it down enough?

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You're done when every factor appears separately with multiplication symbols between them. No exponents should remain - everything should be written as repeated multiplication.

What if the exponent was bigger, like y⁵?

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Same process! y5=yyyyy y^5 = y \cdot y \cdot y \cdot y \cdot y . Just write the variable as many times as the exponent indicates, connected by multiplication symbols.

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