Calculate (-2)³ + 2³: Adding Positive and Negative Cubes

To solve this problem, we'll follow these steps:

• Step 1: Compute $(-2)^3$.
• Step 2: Compute $2^3$.
• Step 3: Add the two results.

Now, let's work through each step:

Step 1: $(-2)^3$ means multiplying $-2$ by itself three times.

$(-2)^3 = (-2) \times (-2) \times (-2)$

Start by multiplying the first two $-2$'s: $(-2) \times (-2) = 4$ (since the product of two negatives is positive).

Next, multiply the result by the third $-2$: $4 \times (-2) = -8$.

Therefore, $(-2)^3 = -8$.

Step 2: Compute $2^3$.

$2^3 = 2 \times 2 \times 2$

Multiply the first two 2's: $2 \times 2 = 4$.

Then multiply the result by the third 2: $4 \times 2 = 8$.

Therefore, $2^3 = 8$.

Step 3: Add the two results together.

We have $(-2)^3 + 2^3 = -8 + 8$.

Calculate the sum: $-8 + 8 = 0$.

Therefore, the solution to the problem is $0$.