Calculate Jonathan's Average Speed: Varying Speeds Over 3-Hour Cycling Competition

Question

Jonathan is reviewing his cycling records from his last competition.

During the first half hour, he rode at a speed of 28 km/h.

The following two hours, he rode at a speed of 24 km/h, then 15 minutes downhill at a speed of 32 km/h, before continuing for another hour at a speed of 27 km/h.

What was his average speed?

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Calculate the distance for each segment.
  • Step 2: Sum all distances for the total distance.
  • Step 3: Sum all time intervals for the total time.
  • Step 4: Use the average speed formula to find the solution.

Now, let's work through each step:
Step 1: Calculate the distance for each segment.
- First 30 minutes (0.5 hours) at 28 km/h: Distance=28×0.5=14\text{Distance} = 28 \times 0.5 = 14 km.
- Next 2 hours at 24 km/h: Distance=24×2=48\text{Distance} = 24 \times 2 = 48 km.
- Next 15 minutes (0.25 hours) at 32 km/h: Distance=32×0.25=8\text{Distance} = 32 \times 0.25 = 8 km.
- Final 1 hour at 27 km/h: Distance=27×1=27\text{Distance} = 27 \times 1 = 27 km.

Step 2: Total distance: 
Total Distance=14+48+8+27=97\text{Total Distance} = 14 + 48 + 8 + 27 = 97 km.

Step 3: Total time: 
Total Time=0.5+2+0.25+1=3.75\text{Total Time} = 0.5 + 2 + 0.25 + 1 = 3.75 hours.

Step 4: Calculate the average speed:
Average Speed=973.7525.888...\text{Average Speed} = \frac{97}{3.75} \approx 25.888... km/h.

Therefore, the solution to the problem is 25.888....

Answer

25.888...