Calculating the Break: Driver's Average Speed Conundrum at 54 km/h

Average Speed with Time Intervals

The owner of a pizzeria suspects that one of his delivery drivers has taken too long of a break.

He knows that the driver traveled for 45 minutes at a speed of 90 km/h and then quickly returned the same way at a speed of 67.5 km/h.

In the middle, he took a break. The manager also knows that the driver's average speed throughout the day is 54 km/h.

How long was the break?

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1

Understand the problem

The owner of a pizzeria suspects that one of his delivery drivers has taken too long of a break.

He knows that the driver traveled for 45 minutes at a speed of 90 km/h and then quickly returned the same way at a speed of 67.5 km/h.

In the middle, he took a break. The manager also knows that the driver's average speed throughout the day is 54 km/h.

How long was the break?

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Convert the driver's travel time from minutes to hours.
  • Step 2: Calculate the total distance for each leg of the trip.
  • Step 3: Determine the driver's total time using the average speed formula.
  • Step 4: Calculate the break time by subtracting travel times from the total time.

Now, let's work through each step:
Step 1: The driver's travel time is given as 45 minutes, which is 4560=0.75 \frac{45}{60} = 0.75 hours.
Step 2: Calculate the distance for each trip. For the forward trip at 90 km/h:
Distance=90×0.75=67.5 \text{Distance} = 90 \times 0.75 = 67.5 km.
The return trip covers the same distance of 67.5 km at 67.5 km/h, taking 67.567.5=1 \frac{67.5}{67.5} = 1 hour.
Step 3: Using the given average speed 54 54 km/h, set up the equation for the total trip:
54=Total DistanceTotal Time 54 = \frac{\text{Total Distance}}{\text{Total Time}}
The total distance traveled each way is 67.5 67.5 , resulting in a round trip of 2×67.5=135 2 \times 67.5 = 135 km.
Let T T be the total time:
54=135T 54 = \frac{135}{T}
Solving for T T , we get:
T=13554=2.5 T = \frac{135}{54} = 2.5 hours.
Step 4: Calculate the break time. The total traveling time is 0.75+1=1.75 0.75 + 1 = 1.75 hours. Thus, break time is:
2.51.75=0.75 2.5 - 1.75 = 0.75 hours or 45 45 minutes.

Therefore, the break taken by the delivery driver was 45 45 minutes.

3

Final Answer

45 minutes

Key Points to Remember

Essential concepts to master this topic
  • Formula: Average speed equals total distance divided by total time
  • Technique: Calculate each leg separately: 90 × 0.75 = 67.5 km
  • Check: Total time 2.5 hours with 135 km gives 54 km/h ✓

Common Mistakes

Avoid these frequent errors
  • Adding speeds instead of using distance-time relationship
    Don't add 90 + 67.5 = 157.5 km/h and divide by 2 = 78.75 km/h! This ignores different time periods for each speed. Always calculate total distance and total time separately, then divide distance by time.

Practice Quiz

Test your knowledge with interactive questions

What is the average speed according to the data?

TravelTimekm/hDistance3122.570400100210400250

FAQ

Everything you need to know about this question

Why can't I just average the two speeds?

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Because the driver spent different amounts of time at each speed! Simple averaging only works when time periods are equal. Here, 45 minutes forward vs 1 hour return requires the weighted average approach.

How do I convert minutes to hours correctly?

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Divide minutes by 60: 4560=0.75 \frac{45}{60} = 0.75 hours. Always use the same units throughout your calculation - don't mix hours and minutes!

What if the break time comes out negative?

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A negative break time means your calculation has an error! Check that you've correctly calculated both distances and travel times before finding total time.

Why does the return trip take exactly 1 hour?

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Because distance = speed × time, so time = distance ÷ speed. The return trip: 67.5 km67.5 km/h=1 hour \frac{67.5 \text{ km}}{67.5 \text{ km/h}} = 1 \text{ hour} . When distance equals speed numerically, time is always 1 hour!

How do I check if my total time is reasonable?

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Use the average speed formula: 54=135T 54 = \frac{135}{T} , so T=13554=2.5 T = \frac{135}{54} = 2.5 hours. This should equal travel time + break time.

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