A hardware factory that manufactured screws for one entire week.
Every day there were 300 screws manufactured.
On the second day, 14 screws were defective and and had to be thrown away.
Similarly, on the fourth day 7 screws were thrown away, and on the fifth day 26 screws were thrown away.
How many good screws were manufactured that week?
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A hardware factory that manufactured screws for one entire week.
Every day there were 300 screws manufactured.
On the second day, 14 screws were defective and and had to be thrown away.
Similarly, on the fourth day 7 screws were thrown away, and on the fifth day 26 screws were thrown away.
How many good screws were manufactured that week?
First, we calculate how many screws the factory produces in total in 7 days:
Now we subtract the number of defective screws that we know the factory discarded on the second day:
Now let's count the number of defective screws that we know the factory discarded on the fourth day:
Now we record the number of defective screws that we know the factory discarded on the fifth day:
2053
\( 74+32+6+4+4=\text{?} \)
Because the defective screws are part of the daily 300! Each day still produces exactly 300 screws - some are just thrown away later. Calculate total production first, then subtract defectives.
Only count the defective screws that are specifically mentioned in the problem. Assume all other days had zero defective screws unless told otherwise.
Use this order: 1) Total production = 7 × 300 = 2100, 2) List all defectives: 14 + 7 + 26 = 47, 3) Good screws = 2100 - 47 = 2053
Yes! That's actually more efficient: 14 + 7 + 26 = 47 total defectives, then 2100 - 47 = 2053. Both methods give the same answer.
Your good screws should be less than total production but close to it. Here: 2053 is less than 2100 ✓, and only 47 screws were defective, which seems reasonable for a week's production.
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