**Let's see an example:**

$X\times2=2\times X$

**We can replace the X with a number:**

$X=3$

**We get:**

$2\times3=6$

$3\times2=6$

As you can see, it doesn't matter in what order we multiply the factors, we still get the same correct answer.

**Note** that the commutative property of multiplication **does not** work with division.

Starting to get it? Keep practicing to turn this new property into muscle memory.

## Exercises with the commutative property of multiplication

### Exercise 1

**Task:**

$5.25\cdot\frac{2}{3}\cdot\frac{7}{21}=\text{?}$

**Solution:**

First, we convert the decimal number into a mixed fraction.

$5\frac{1}{4}\cdot\frac{2}{3}\cdot\frac{7}{21}=$

Then, we convert the mixed fraction into a simple fraction.

$\frac{5\times4+1}{4}\cdot\frac{2}{3}\cdot\frac{7}{21}=$

$\frac{21}{4}\cdot\frac{2}{3}\cdot\frac{7}{21}=$

Notice that you can reduce to 21 and get a simpler expression.

$\frac{7}{4}\cdot\frac{2}{3}=$

We multiply the numerator by the numerator and the denominator by the denominator.

$\frac{7\times2}{4\times3}=$

$\frac{14}{12}=$

We continue to reduce as much as possible.

$1\frac{2}{12}=$

$1\frac{1}{6}$

**Answer:**

$1\frac{1}{6}$

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### Exercise 2

**Task:**

$4\frac{1}{4}\cdot3\frac{4}{9}\cdot3\frac{1}{17}=\text{?}$

**Solution**:

First, we convert all mixed fractions to simple fractions.

$\frac{4\times4+1}{4}\times\frac{3\times9+4}{9}\times\frac{3\times17+1}{17}=$

$\frac{16+1}{4}\times\frac{27+4}{9}\times\frac{51+1}{17}=$

$\frac{17}{4}\times\frac{31}{9}\times\frac{52}{17}=$

We reduce to $17$

$\frac{52}{4}\times\frac{31}{9}=$

We divide $52$ by $4$ and solve

$13\times\frac{31}{9}=$

$\frac{403}{9}=44\frac{7}{9}$

**Answer:**

$44\frac{7}{9}$

### Exercise 3

**Task:**

$(7+2+3)(7+6)(12-3-4)=\text{?}$

**Solution:**

We start by solving each of the parentheses in the order of operations.

$(9+3)\times13\times(9-4)=$

$12\times13\times5=$

We move the 5 to the left so that we can easily solve the exercise from left to right

$12\times5\times13=$

$60\times13=780$

**Answer:**

$780$

Do you know what the answer is?

### Exercise 4

**Task:**

$5\cdot7\cdot13\cdot6=\text{?}$

**Solution:**

We reorder the exercise into two smaller expressions so that they are simpler to solve.

$7\cdot13\cdot6\operatorname{\cdot}5=$

We start by solving the first expression in the exercise, and then the second.

Then we solve the whole, simplified expression.

$91\cdot30=2730$

**Answer:**

$2730$

### Exercise 5

**Task:**

$5\cdot17\cdot2=\text{?}$

**Solution:**

We reorder the exercise to make it easier to solve.

$5\cdot2\cdot17=$

We continue solving the exercise from left to right.

$10\cdot17=170$

**Answer:**

$170$

## Review questions

**What is the commutative property in multiplication?**

The commutative property of multiplication tells us that changing the order of the factors in an expression won't change the end result

For example, we will get the same answer if we multiply $3\times16$ or if we multiply $16\times3$, in both cases the result is $48$.

**How does the commutative property work in multiplication?**

The commutative property in multiplication can be understood as follows: $a\times b=b\times a$

This means that the order of the factors does not change the result. If we assign values to $a=4$ and $b=6$, applying the commutative property we will get:

$4\times6=24$

$6\times4=24$

We can see that in both cases it gave us the same result even though the factors are in a different order.

**What are the 4 properties of multiplication?**

The 4 properties of multiplication are the following:

**Commutative:** No matter the order of the factors, the result will be the same $a\times b=b\times a$**Associative:** No matter how we group sets of factors, the result will be the same. $a\times\left(b\times c\right)=\left(a\times b\right)\times c$**Distributive:** Multiplying a factor by the sum of two addends is the same as multiplying by each addend separately and then adding the results together. $a\times\left(b+c\right)=a\times b+a\times c$**Identity element:** The identity element of multiplication is 1, because if we multiply a number by the number $1$, the result will still be that number. This can be understood as follows $a\times1=a$.

Do you think you will be able to solve it?

## Examples with solutions for The Commutative Property of Multiplication

### Exercise #1

### Video Solution

### Step-by-Step Solution

We use the substitution property and add parentheses for the addition operation:

$(2+1)-3=$

Now, we solve the exercise according to the order of operations:

$2+1=3$

$3-3=0$

### Answer

### Exercise #2

### Video Solution

### Step-by-Step Solution

We will use the substitution property to arrange the exercise a bit more comfortably, we will add parentheses to the addition operation:

$(3+2+1)-4=$

We first solve the addition, from left to right:

$3+2=5$

$5+1=6$

And finally, we subtract:

$6-4=2$

### Answer

### Exercise #3

### Video Solution

### Step-by-Step Solution

According to the order of operations, addition and subtraction are on the same level and, therefore, must be resolved from left to right.

However, in the exercise we can use the substitution property to make solving simpler.

-5+4+1-3

4+1-5-3

5-5-3

0-3

-3

### Answer

### Exercise #4

### Video Solution

### Step-by-Step Solution

In this exercise, it is not possible to use the substitution property, therefore we solve it as is from left to right according to the order of arithmetic operations.

That is, we first solve the multiplication exercise and then we add:

$11\times3=33$

$33+7=40$

### Answer

### Exercise #5

### Video Solution

### Step-by-Step Solution

According to the order of operations, we start with the multiplication exercise and then with the addition.

$12\times13=156$

Now we get the exercise:

$156+14=170$

### Answer