Calculate Point B on the Graph of f(x) = x² - 6x + 8

To calculate point B, we should determine the vertex of the quadratic function $f(x) = x^2 - 6x + 8$.

The x-coordinate of the vertex can be found using the formula $x = -\frac{b}{2a}$.

In our equation, we have $a = 1$ and $b = -6$, therefore:

$x = -\frac{-6}{2 \times 1} = \frac{6}{2} = 3$

Next, we substitute $x = 3$ back into the function to find the y-coordinate:

$f(3) = 3^2 - 6 \times 3 + 8 = 9 - 18 + 8 = -1$

Thus, the vertex, which is point B, is $(3, -1)$.

Therefore, the solution indicates that point B is at $(3, -1)$.