What is the area of a rectangle with sides of x-7 and x+8?
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What is the area of a rectangle with sides of x-7 and x+8?
To tackle this problem, we must compute the area of a rectangle given its sides are expressed as and .
Step 1: Start by recognizing the formula used to calculate the area of a rectangle: the product of its length and width.
Step 2: Substitute the given expressions for length and width into this formula:
Step 3: Multiply the binomial expressions using the distributive property, often referred to as the FOIL method (First, Outer, Inner, Last).
Step 4: Combine all these products into a single polynomial expression:
Step 5: Simplify by combining like terms:
Therefore, the area of the rectangle is given by the polynomial expression: .
\( x^2+6x+9=0 \)
What is the value of X?
Area requires multiplication, not addition! Adding gives you the perimeter formula. For rectangles, you must multiply length times width: .
FOIL means First, Outer, Inner, Last - the four products when multiplying binomials. It ensures you don't miss any terms when expanding .
Look for like terms - terms with the same variable and exponent. In this problem, combine and because they're both x terms: .
Yes! If x < 7, then (x-7) is negative. Since areas represent real measurements, this tells us the rectangle only exists when both dimensions are positive.
Pick a simple value for x (like x = 10) and calculate both and your expanded form. Both should give the same result: and ✓
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