Calculate Rectangle Area: Solve for X Given X-6 Dimensions

Question

Given a rectangle whose side is smaller by 6 than the other side. We mark the area of the rectangle with S

and the large side with X

Check the correct argument:

XXXX-6X-6X-6

Video Solution

Solution Steps

00:00 Find the correct expression for the rectangle's area
00:03 We'll use the formula for calculating rectangle area (side times side)
00:12 Open parentheses properly, multiply by each factor
00:19 Add 9 to each side of the equation
00:33 Use the shortened multiplication formulas to convert parentheses
00:36 Isolate the area back
00:40 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we need to express the area of the rectangle in terms of X X , accounting for the relationship between its sides.

Step 1: Calculate the area of the rectangle.
The area s s of a rectangle is obtained by multiplying the length by the width:

s=X×(X6) s = X \times (X - 6)

Expanding the expression gives us:

s=X26X s = X^2 - 6X

We want to express this in a form that matches the given answer choices. Recognizing the square of a binomial will help us reformulate:

s=X26X s = X^2 - 6X can be related to a square of a binomial by adjusting it:

Step 2: Recast into a recognizable square:
We want to find a relation to (x3)2(x-3)^2, so bear in mind:

(X3)2=X26X+9 (X - 3)^2 = X^2 - 6X + 9

Therefore, rearranging in the form of (X3)2(X - 3)^2, we derive:

s=(X3)29 s = (X - 3)^2 - 9

Therefore, the area of the rectangle, expressed in a way to match the correct choices, is s=(x3)29 s = (x - 3)^2 - 9 , which corresponds to choice 3 from the given options.

The correct choice is: Choice 3: s=(x3)29 s=(x-3)^2-9 .

Answer

s=(x3)29 s=(x-3)^2-9