Trapezoid Area Formula: Height Equals Sum of Bases with X-5 Difference

Given a trapezoid whose height is equal to the sum of the two bases.

It is known that the difference between the large base and the small base is equal to 5. We will mark the large base with X

Express the area of the trapezoid using X

X-5X-5X-5XXX2X-52X-52X-5

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Express the area of the trapezoid using X
00:03 Use the formula for calculating the area of a trapezoid
00:07 (sum of bases) times height divided by 2
00:21 Let's take the fraction out of the parentheses
00:36 The same factor multiplied by itself is actually squared
00:40 Use the shortened multiplication formulas to expand the parentheses
00:49 Calculate the squares and products
01:01 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

Given a trapezoid whose height is equal to the sum of the two bases.

It is known that the difference between the large base and the small base is equal to 5. We will mark the large base with X

Express the area of the trapezoid using X

X-5X-5X-5XXX2X-52X-52X-5

2

Step-by-step solution

To express the area of the trapezoid in terms of X X , we follow these steps:

  • Step 1: Identify given measurements of the trapezoid.
    • Large base =X = X .
    • Small base =X5 = X - 5 .
    • Height =2X5 = 2X - 5 .
  • Step 2: Use the trapezoid area formula: Area=12×(Base1+Base2)×Height \text{Area} = \frac{1}{2} \times (\text{Base}_1 + \text{Base}_2) \times \text{Height}
  • Step 3: Substitute the values: Area=12×(X+(X5))×(2X5) \text{Area} = \frac{1}{2} \times (X + (X - 5)) \times (2X - 5)
  • Step 4: Simplify the expression: Area=12×(2X5)×(2X5) \text{Area} = \frac{1}{2} \times (2X - 5) \times (2X - 5) Area=12×(2X5)2 \text{Area} = \frac{1}{2} \times (2X - 5)^2 Area=12×(4X220X+25) \text{Area} = \frac{1}{2} \times (4X^2 - 20X + 25)
  • Step 5: Conclude with the expression for the area: Area=12[4X220X+25] \text{Area} = \frac{1}{2}[4X^2 - 20X + 25]

Therefore, the expression for the area of the trapezoid in terms of X X is 12[4X220X+25] \frac{1}{2}[4X^2 - 20X + 25] .

3

Final Answer

12[4x220x+25] \frac{1}{2}\lbrack4x^2-20x+25\rbrack

Practice Quiz

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Declares the given expression as a sum

\( (7b-3x)^2 \)

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