Calculate Snail's Daily Distance: 3 Days, 40 Meters Back

Linear Equations with Distance Variables

A snail travels across several set distances each day. On the first day, it crosses 3 such distances and on the second day it covers 5 such distances. On the third day, it goes backwards 40 meters and reaches its starting point.

What is the length of each set distance the snail crosses?

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Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

A snail travels across several set distances each day. On the first day, it crosses 3 such distances and on the second day it covers 5 such distances. On the third day, it goes backwards 40 meters and reaches its starting point.

What is the length of each set distance the snail crosses?

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Define the distance the snail travels each time as a variable.
  • Step 2: Set up an algebraic equation reflecting the snail's total movement.
  • Step 3: Solve the equation for the unknown variable.

Now, let's work through each step:
Step 1: Let x x represent the length of each set distance.
Step 2: The total forward distance over the first two days is 3x+5x=8x 3x + 5x = 8x .
The backward movement on the third day is 40 meters.
Since the snail ends up at the starting point, the equation is 8x=40 8x = 40 .
Step 3: Solve for x x :
8x=40    x=408=5 8x = 40 \implies x = \frac{40}{8} = 5

Therefore, the solution to the problem is x=5 x = 5 meters.

3

Final Answer

5 meters

Key Points to Remember

Essential concepts to master this topic
  • Setup: Define unknown distance as variable, track total movement
  • Technique: Forward distance 3x + 5x = 8x equals backward 40m
  • Check: Substitute x = 5: 8(5) = 40 meters total ✓

Common Mistakes

Avoid these frequent errors
  • Adding backward distance instead of subtracting
    Don't write 3x + 5x + 40 = 0 for total movement! The snail goes backward 40m to return to start, so forward distance must equal backward distance. Always set forward movement equal to backward movement: 8x = 40.

Practice Quiz

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\( x+x=8 \)

FAQ

Everything you need to know about this question

Why does the snail end up at the starting point?

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The problem states that after going backward 40 meters on day 3, the snail reaches its starting point. This means the total forward distance from days 1 and 2 exactly equals the 40-meter backward movement.

How do I know which direction is positive?

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Choose forward movement as positive and backward as negative. Since the snail returns to start, the net displacement is zero: forward distance - backward distance = 0.

What if I set up the equation differently?

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You could write 3x + 5x - 40 = 0, which gives the same result! Both setups work as long as you're consistent with positive/negative directions.

Can the distance be negative?

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No! Distance is always positive. If you get a negative answer, check your equation setup - you might have mixed up the directions.

How do I verify my answer makes sense?

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Check that forward distance equals backward distance: 3(5) + 5(5) = 15 + 25 = 40 meters forward, and 40 meters backward. The snail returns exactly to start! ✓

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