Calculate Square Perimeter: Solving (√3·√12-5)²·3² Side Length Problem

Square Perimeter with Radical Simplification

A square has a side length of

(3125)232 (\sqrt{3}\cdot\sqrt{12}-5)^2\cdot3^2 .

Calculate its perimeter.

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Determine the perimeter of the square
00:04 Start by calculating the side length
00:09 Square root of number(A) times square root of number(B)
00:12 Equals the square root of their product (A times B)
00:17 Let's use this formula in our exercise
00:24 Calculate the product
00:32 Calculate the root and substitute
00:37 Solve the parentheses
00:44 1 to the power of any number always equals 1
00:52 This is the side length of the square
00:55 In a square all sides are equal
01:00 Calculate the perimeter
01:03 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

A square has a side length of

(3125)232 (\sqrt{3}\cdot\sqrt{12}-5)^2\cdot3^2 .

Calculate its perimeter.

2

Step-by-step solution

To calculate the perimeter of a square, we need to first determine the length of one side and then use the formula for the perimeter of a square, which is given by 4×side length 4 \times \text{side length} .

The side length is given as (3125)232 (\sqrt{3}\cdot\sqrt{12}-5)^2\cdot3^2 . Let's simplify this expression step by step:

  • First, simplify the square roots: 3 \sqrt{3} and 12 \sqrt{12} .

    • 12=4×3=4×3=2×3 \sqrt{12} = \sqrt{4 \times 3} = \sqrt{4}\times \sqrt{3} = 2 \times \sqrt{3}
    • Thus, 3×12=3×2×3=2×3=6 \sqrt{3} \times \sqrt{12} = \sqrt{3} \times 2 \times \sqrt{3} = 2 \times 3 = 6 .
  • Next, substitute back into the expression: (65)232 (6 - 5)^2 \cdot 3^2 .
  • Simplify inside the parentheses: 65=1 6 - 5 = 1 , so we have 1232 1^2 \cdot 3^2 .
  • Calculate the squares: 12=1 1^2 = 1 and 32=9 3^2 = 9 .
  • Multiply the results: 1×9=9 1 \times 9 = 9 .

The side length of the square is therefore 9 9 .

Thus, the perimeter of the square is:

  • 4×9=36 4 \times 9 = 36 .

Therefore, the perimeter of the square is 36 36 .

3

Final Answer

36

Key Points to Remember

Essential concepts to master this topic
  • Radical Property: Use ab=ab \sqrt{a} \cdot \sqrt{b} = \sqrt{ab} to simplify products
  • Technique: Factor perfect squares: 12=4×3=23 \sqrt{12} = \sqrt{4 \times 3} = 2\sqrt{3}
  • Check: Verify side length 9 gives perimeter 4×9=36 4 \times 9 = 36

Common Mistakes

Avoid these frequent errors
  • Calculating perimeter before simplifying the side length expression
    Don't multiply by 4 before simplifying (3125)232 (\sqrt{3}\cdot\sqrt{12}-5)^2\cdot3^2 = wrong formula application! This leads to complex calculations with radicals. Always simplify the side length completely first, then multiply by 4.

Practice Quiz

Test your knowledge with interactive questions

\( 6+\sqrt{64}-4= \)

FAQ

Everything you need to know about this question

Why can't I just multiply the whole expression by 4 right away?

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You need to find the actual side length first! The expression (3125)232 (\sqrt{3}\cdot\sqrt{12}-5)^2\cdot3^2 simplifies to 9, so the perimeter is 4 × 9 = 36, not 4 times the complex expression.

How do I simplify 312 \sqrt{3} \cdot \sqrt{12} ?

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Use the property ab=ab \sqrt{a} \cdot \sqrt{b} = \sqrt{ab} ! So 312=36=6 \sqrt{3} \cdot \sqrt{12} = \sqrt{36} = 6 . Or factor: 12=23 \sqrt{12} = 2\sqrt{3} , so 323=23=6 \sqrt{3} \cdot 2\sqrt{3} = 2 \cdot 3 = 6 .

What if I get a negative number inside the parentheses?

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In this problem, 312=6 \sqrt{3}\cdot\sqrt{12} = 6 and 65=1 6 - 5 = 1 , which is positive! If you got negative, double-check your radical multiplication.

Why does (1)232 (1)^2 \cdot 3^2 equal 9?

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Because any number to the power of 2 means multiply by itself: 12=1×1=1 1^2 = 1 \times 1 = 1 and 32=3×3=9 3^2 = 3 \times 3 = 9 . Then 1×9=9 1 \times 9 = 9 .

How can I check if my final answer is correct?

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Substitute back! If the side length is 9, then the perimeter should be 4×9=36 4 \times 9 = 36 . Also verify that (3125)232=(65)29=19=9 (\sqrt{3}\cdot\sqrt{12}-5)^2\cdot3^2 = (6-5)^2\cdot9 = 1\cdot9 = 9

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