Calculate Square Perimeter: Solving (√3·√12-5)²·3² Side Length Problem

Question

A square has a side length of

(3125)232 (\sqrt{3}\cdot\sqrt{12}-5)^2\cdot3^2 .

Calculate its perimeter.

Video Solution

Solution Steps

00:00 Find the perimeter of the square
00:04 Let's start by calculating the side length
00:09 Square root of number(A) times square root of number(B)
00:12 Equals the square root of their product (A times B)
00:17 Let's use this formula in our exercise
00:24 Let's calculate the product
00:32 Let's calculate the root and substitute
00:37 Let's solve the parentheses
00:44 1 to the power of any number always equals 1
00:52 This is the side length of the square
00:55 In a square all sides are equal
01:00 Let's calculate the perimeter
01:03 And this is the solution to the question

Step-by-Step Solution

To calculate the perimeter of a square, we need to first determine the length of one side and then use the formula for the perimeter of a square, which is given by 4×side length 4 \times \text{side length} .

The side length is given as (3125)232 (\sqrt{3}\cdot\sqrt{12}-5)^2\cdot3^2 . Let's simplify this expression step by step:

  • First, simplify the square roots: 3 \sqrt{3} and 12 \sqrt{12} .

    • 12=4×3=4×3=2×3 \sqrt{12} = \sqrt{4 \times 3} = \sqrt{4}\times \sqrt{3} = 2 \times \sqrt{3}
    • Thus, 3×12=3×2×3=2×3=6 \sqrt{3} \times \sqrt{12} = \sqrt{3} \times 2 \times \sqrt{3} = 2 \times 3 = 6 .
  • Next, substitute back into the expression: (65)232 (6 - 5)^2 \cdot 3^2 .
  • Simplify inside the parentheses: 65=1 6 - 5 = 1 , so we have 1232 1^2 \cdot 3^2 .
  • Calculate the squares: 12=1 1^2 = 1 and 32=9 3^2 = 9 .
  • Multiply the results: 1×9=9 1 \times 9 = 9 .

The side length of the square is therefore 9 9 .

Thus, the perimeter of the square is:

  • 4×9=36 4 \times 9 = 36 .

Therefore, the perimeter of the square is 36 36 .

Answer

36