Calculate the Day: Solving for When Daniel's Savings Reach Exactly $29

Arithmetic Sequences with Real-World Applications

Daniel bought a piggy bank. On the first day, he put in $15 and every day he adds $2. Is it possible for Daniel to save exactly $ 29? If so, when?

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:13 Can we save 29 shekels? If yes, on which day does it happen?
00:18 Let's find the day when the total savings equals 29.
00:24 We'll use the arithmetic sequence formula to figure out the day.
00:28 Next, substitute the values from the problem into the formula to find N.
00:45 Our goal is to solve for N, which represents the day.
01:01 Let's simplify the equation as much as we can.
01:07 Now, we'll isolate the unknown, N, to find the day.
01:14 And that's how we find the solution to our question!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Daniel bought a piggy bank. On the first day, he put in $15 and every day he adds $2. Is it possible for Daniel to save exactly $ 29? If so, when?

2

Step-by-step solution

To determine if Daniel can save exactly $29, we model his savings as an arithmetic sequence.

  • Step 1: Identify the given information

Initially, Daniel puts in $15, and he adds $2 daily. We are looking for the day when the total savings equals $29.

  • Step 2: Set up the sequence formula

The nn-th term of an arithmetic sequence is given by:

an=a1+(n1)d a_n = a_1 + (n-1) \cdot d

Where:

  • a1=15a_1 = 15, the amount on the first day
  • d=2d = 2, the daily addition
  • an=29a_n = 29, the amount we want to achieve
  • Step 3: Solve for nn

Set up the equation:

29=15+(n1)2 29 = 15 + (n-1) \cdot 2

Simplifying:

29=15+2n2 29 = 15 + 2n - 2

29=13+2n 29 = 13 + 2n

16=2n 16 = 2n

n=8 n = 8

Therefore, Daniel will have exactly $29 on the eighth day.

Conclusion:

Yes, it is possible for Daniel to save exactly $29, and it will occur on the eighth day.

3

Final Answer

Yes, on the eighth day.

Key Points to Remember

Essential concepts to master this topic
  • Formula: Use a_n = a_1 + (n-1) × d for arithmetic sequences
  • Technique: Substitute known values: 29 = 15 + (n-1) × 2
  • Check: Verify day 8: 15 + 7 × 2 = 29 ✓

Common Mistakes

Avoid these frequent errors
  • Confusing day number with number of additions
    Don't count the initial $15 as day zero = off-by-one error! This makes students think day 7 instead of day 8. Always remember the first day already has $15, so additional days start from day 2.

Practice Quiz

Test your knowledge with interactive questions

Look at the following set of numbers and determine if there is any property, if so, what is it?

\( 94,96,98,100,102,104 \)

FAQ

Everything you need to know about this question

Why isn't the answer day 7 if we add $14 more?

+

Great observation! We do add $14 more (7 × $2), but remember Daniel already had $15 on day 1. So $15 + $14 = $29 happens on day 8, not day 7.

What if the target amount wasn't possible to reach?

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You'd get a non-integer value for n! For example, if targeting $28, you'd get n = 7.5, which means it's impossible since Daniel can't save on half-days.

How do I set up the arithmetic sequence formula?

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Identify three things: first term (a_1 = initial amount), common difference (d = daily addition), and target term (a_n = amount you want).

Can I solve this without the arithmetic sequence formula?

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Yes! You could list out each day: Day 1: $15, Day 2: $17, Day 3: $19... until you reach $29. But the formula is much faster for larger numbers!

What does 'n-1' mean in the formula?

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The (n-1) represents how many times we've added the common difference. On day n, we've only added d a total of (n-1) times since day 1 already had the first term.

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