Daniel bought a piggy bank. On the first day, he put in $15 and every day he adds $2. Is it possible for Daniel to save exactly $ 29? If so, when?
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Daniel bought a piggy bank. On the first day, he put in $15 and every day he adds $2. Is it possible for Daniel to save exactly $ 29? If so, when?
To determine if Daniel can save exactly $29, we model his savings as an arithmetic sequence.
Initially, Daniel puts in $15, and he adds $2 daily. We are looking for the day when the total savings equals $29.
The -th term of an arithmetic sequence is given by:
Where:
Set up the equation:
Simplifying:
Therefore, Daniel will have exactly $29 on the eighth day.
Conclusion:
Yes, it is possible for Daniel to save exactly $29, and it will occur on the eighth day.
Yes, on the eighth day.
Look at the following set of numbers and determine if there is any property, if so, what is it?
\( 94,96,98,100,102,104 \)
Great observation! We do add $14 more (7 × $2), but remember Daniel already had $15 on day 1. So $15 + $14 = $29 happens on day 8, not day 7.
You'd get a non-integer value for n! For example, if targeting $28, you'd get n = 7.5, which means it's impossible since Daniel can't save on half-days.
Identify three things: first term (a_1 = initial amount), common difference (d = daily addition), and target term (a_n = amount you want).
Yes! You could list out each day: Day 1: $15, Day 2: $17, Day 3: $19... until you reach $29. But the formula is much faster for larger numbers!
The (n-1) represents how many times we've added the common difference. On day n, we've only added d a total of (n-1) times since day 1 already had the first term.
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