Daniel bought a piggy bank. On the first day, he put in $15 and every day he adds $2. Is it possible for Daniel to save exactly $ 29? If so, when?
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Daniel bought a piggy bank. On the first day, he put in $15 and every day he adds $2. Is it possible for Daniel to save exactly $ 29? If so, when?
To determine if Daniel can save exactly $29, we model his savings as an arithmetic sequence.
Initially, Daniel puts in $15, and he adds $2 daily. We are looking for the day when the total savings equals $29.
The -th term of an arithmetic sequence is given by:
Where:
Set up the equation:
Simplifying:
Therefore, Daniel will have exactly $29 on the eighth day.
Conclusion:
Yes, it is possible for Daniel to save exactly $29, and it will occur on the eighth day.
Yes, on the eighth day.
12 ☐ 10 ☐ 8 7 6 5 4 3 2 1
Which numbers are missing from the sequence so that the sequence has a term-to-term rule?
Great observation! We do add $14 more (7 × $2), but remember Daniel already had $15 on day 1. So $15 + $14 = $29 happens on day 8, not day 7.
You'd get a non-integer value for n! For example, if targeting $28, you'd get n = 7.5, which means it's impossible since Daniel can't save on half-days.
Identify three things: first term (a_1 = initial amount), common difference (d = daily addition), and target term (a_n = amount you want).
Yes! You could list out each day: Day 1: $15, Day 2: $17, Day 3: $19... until you reach $29. But the formula is much faster for larger numbers!
The (n-1) represents how many times we've added the common difference. On day n, we've only added d a total of (n-1) times since day 1 already had the first term.
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