A truck travels for 4 hours at a speed of 30 km/h, then for 3 hours at a speed of 50 km/h.
If its average speed during 15 hours is 5X km/h, then what is its speed after the first 7 hours of travel?
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A truck travels for 4 hours at a speed of 30 km/h, then for 3 hours at a speed of 50 km/h.
If its average speed during 15 hours is 5X km/h, then what is its speed after the first 7 hours of travel?
To solve this problem, we'll follow these steps:
Now, let's work through these steps:
Step 1: Calculate the distance in the first 4 hours traveling at 30 km/h.
The distance is .
Next, calculate the distance in the next 3 hours traveling at 50 km/h.
The distance is .
Total distance covered in the first 7 hours is .
Step 2: Calculate total distance over 15 hours using the average speed.
The average speed is given as , thus:
.
Step 3: Determine the distance covered in the remaining 8 hours.
.
Since this remaining distance is covered in 8 hours, the speed after the first 7 hours of travel is:
.
Calculating this gives:
km/h.
Therefore, the speed after the first 7 hours of travel is km/h.
km/h
Norbert buys some new clothes.
When he gets home, he decides to work out how much each outfit cost him on average.
What answer should he come up with?
Because average speed depends on time, not just the speeds themselves! The truck spends different amounts of time at each speed, so you must calculate total distance first.
The 5X represents a variable coefficient - it means the average speed is 5 times some unknown value X. This creates an algebraic relationship you can solve for.
The problem asks for the speed after 7 hours, implying a single constant speed for the remaining time. This is a common assumption in multi-segment motion problems.
No, because the average speed is given as 5X km/h, not a specific number. The variable X is essential - your final answer will be an expression containing X.
When you divide 75 by 8, you get 9.375 (which equals 9⅜). Decimal coefficients are normal in algebra - just make sure to calculate accurately!
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