In a apartment block there are 20 apartments.
5 apartments house 4 tenants each.
6 apartments house 3 tenants each.
The rest of the apartments house 5 or 7 tenants.
On average each apartment houses tenants.
How many apartments are there where 5 tenants live?
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In a apartment block there are 20 apartments.
5 apartments house 4 tenants each.
6 apartments house 3 tenants each.
The rest of the apartments house 5 or 7 tenants.
On average each apartment houses tenants.
How many apartments are there where 5 tenants live?
To solve this problem, we first note the setup: 5 apartments with 4 tenants and 6 apartments with 3 tenants are explicitly mentioned. That accounts for:
Now, the remaining apartments (since ) can house either 5 or 7 tenants. Let be the number of 5-tenant apartments and be the number of 7-tenant apartments:
The average number of tenants per apartment is given by . We express the total tenant number equation:
Substitute into the tenant equation:
Total number of tenants =
=
=
Average tenants =
Multiplying throughout by 20:
101 - 2x_1 = 20(y - 2)
101 - 2x_1 = 20y - 40
Solving for :
Therefore, .
Thus, the correct answer is .
A hotel's overall rating is determined according to a weighted average of several categories. Each category is given a rating and a weighted factor. Below are the ratings for the "Happy Tourist" hotel:
Determine the hotel's overall rating?
The fractional result represents a relationship, not an actual count! For any specific value of y, this expression must give a whole number between 0 and 9 for the problem to have a real solution.
Let = apartments with 5 tenants and = apartments with 7 tenants. Since there are 9 remaining apartments total, we know .
The average means: Total tenants ÷ 20 apartments = y-2. So total tenants = . This connects our counting to the algebraic expression!
Substituting reduces our system from two equations with two unknowns to one equation with one unknown. This makes solving much easier!
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