Calculate Number of Apartments with 5 Tenants: Solving y-2 Average Equation

System of Equations with Constraints

In a apartment block there are 20 apartments.

5 apartments house 4 tenants each.

6 apartments house 3 tenants each.

The rest of the apartments house 5 or 7 tenants.

On average each apartment housesy2 y-2 tenants.

How many apartments are there where 5 tenants live?

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1

Understand the problem

In a apartment block there are 20 apartments.

5 apartments house 4 tenants each.

6 apartments house 3 tenants each.

The rest of the apartments house 5 or 7 tenants.

On average each apartment housesy2 y-2 tenants.

How many apartments are there where 5 tenants live?

2

Step-by-step solution

To solve this problem, we first note the setup: 5 apartments with 4 tenants and 6 apartments with 3 tenants are explicitly mentioned. That accounts for:

  • 5×4=20 5 \times 4 = 20 tenants from the 4-tenant apartments.
  • 6×3=18 6 \times 3 = 18 tenants from the 3-tenant apartments.

Now, the remaining 9 9 apartments (since 20(5+6)=9 20 - (5 + 6) = 9 ) can house either 5 or 7 tenants. Let x1 x_1 be the number of 5-tenant apartments and x2 x_2 be the number of 7-tenant apartments:

  • x1+x2=9 x_1 + x_2 = 9
  • Total number of tenants = 20+18+5x1+7x2 20 + 18 + 5x_1 + 7x_2

The average number of tenants per apartment is given by y2 y - 2 . We express the total tenant number equation:

20+18+5x1+7x220=y2\frac{20 + 18 + 5x_1 + 7x_2}{20} = y - 2

Substitute x2=9x1 x_2 = 9 - x_1 into the tenant equation:

Total number of tenants = 38+5x1+7(9x1) 38 + 5x_1 + 7(9 - x_1)

= 38+5x1+637x1 38 + 5x_1 + 63 - 7x_1

= 1012x1 101 - 2x_1

Average tenants = 1012x120=y2\frac{101 - 2x_1}{20} = y - 2

Multiplying throughout by 20:

101 - 2x_1 = 20(y - 2)

101 - 2x_1 = 20y - 40

Solving for x1 x_1 :

2x1=20y40101-2x_1 = 20y - 40 - 101

2x1=20y141-2x_1 = 20y - 141

x1=14120y2 x_1 = \frac{141 - 20y}{2}

Therefore, x1=70.510y x_1 = 70.5 - 10y .

Thus, the correct answer is 70.510y\boxed{70.5 - 10y}.

3

Final Answer

70.510y 70.5-10y

Key Points to Remember

Essential concepts to master this topic
  • Setup: Identify known quantities before setting up variables
  • Technique: Use substitution: x2=9x1 x_2 = 9 - x_1 to eliminate one variable
  • Check: Verify x1+x2=9 x_1 + x_2 = 9 and total tenants equals 20(y2) 20(y-2)

Common Mistakes

Avoid these frequent errors
  • Forgetting to account for all apartments
    Don't set up equations using only the variable apartments = incomplete system! Students often forget the 5 apartments with 4 tenants and 6 apartments with 3 tenants contribute 38 total tenants. Always include all given information in your total count before setting up equations.

Practice Quiz

Test your knowledge with interactive questions

A hotel's overall rating is determined according to a weighted average of several categories. Each category is given a rating and a weighted factor. Below are the ratings for the "Happy Tourist" hotel:

SatisfactionCleanlinessServiceBreakfastRatingWeight50%30%10%10%4.5453

Determine the hotel's overall rating?

FAQ

Everything you need to know about this question

Why do we get a fractional answer when counting apartments?

+

The fractional result 70.510y 70.5 - 10y represents a relationship, not an actual count! For any specific value of y, this expression must give a whole number between 0 and 9 for the problem to have a real solution.

How do I know which apartments have 5 tenants vs 7 tenants?

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Let x1 x_1 = apartments with 5 tenants and x2 x_2 = apartments with 7 tenants. Since there are 9 remaining apartments total, we know x1+x2=9 x_1 + x_2 = 9 .

What does the average formula really mean here?

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The average y2 y-2 means: Total tenants ÷ 20 apartments = y-2. So total tenants = 20(y2) 20(y-2) . This connects our counting to the algebraic expression!

Why substitute before solving the equation?

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Substituting x2=9x1 x_2 = 9 - x_1 reduces our system from two equations with two unknowns to one equation with one unknown. This makes solving much easier!

How can I check if my final answer makes sense?

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  • The number of 5-tenant apartments must be between 0 and 9
  • Total tenants should equal 38+5x1+7x2 38 + 5x_1 + 7x_2
  • Average should equal y2 y-2 when calculated ✓

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