Calculate the First Term of the Sequence Using 3n²-4

A sequence has the rule 3n24 3n^2-4 .

What is the first term?

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00:00 Find member 1
00:03 We'll substitute the appropriate member's position in the formula and solve
00:16 Always solve exponents first
00:23 Always solve multiplication and division before addition and subtraction
00:27 And this is the solution to the question

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1

Understand the problem

A sequence has the rule 3n24 3n^2-4 .

What is the first term?

2

Step-by-step solution

To solve this problem, we'll determine the first term of the sequence using the given formula 3n243n^2 - 4.

  • Step 1: Identify that the first term corresponds to n=1n = 1.

  • Step 2: Substitute n=1n = 1 into the formula 3n243n^2 - 4.

  • Step 3: Calculate the value.

Now, let's work through these steps:
Step 1: For n=1n = 1, determine the first term using the sequence formula.
Step 2: Substitute n=1n = 1 into 3n243n^2 - 4:

3(1)24=3×14=34=1 3(1)^2 - 4 = 3 \times 1 - 4 = 3 - 4 = -1

Therefore, the first term of the sequence is 1-1.

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Final Answer

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Is there a term-to-term rule for the sequence below?

18 , 22 , 26 , 30

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