Calculate the First Term of the Sequence Using 3n²-4

Sequence Terms with Quadratic Formulas

A sequence has the rule 3n24 3n^2-4 .

What is the first term?

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Step-by-step video solution

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00:00 Find member 1
00:03 We'll substitute the appropriate member's position in the formula and solve
00:16 Always solve exponents first
00:23 Always solve multiplication and division before addition and subtraction
00:27 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

A sequence has the rule 3n24 3n^2-4 .

What is the first term?

2

Step-by-step solution

To solve this problem, we'll determine the first term of the sequence using the given formula 3n243n^2 - 4.

  • Step 1: Identify that the first term corresponds to n=1n = 1.

  • Step 2: Substitute n=1n = 1 into the formula 3n243n^2 - 4.

  • Step 3: Calculate the value.

Now, let's work through these steps:
Step 1: For n=1n = 1, determine the first term using the sequence formula.
Step 2: Substitute n=1n = 1 into 3n243n^2 - 4:

3(1)24=3×14=34=1 3(1)^2 - 4 = 3 \times 1 - 4 = 3 - 4 = -1

Therefore, the first term of the sequence is 1-1.

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Final Answer

1-

Key Points to Remember

Essential concepts to master this topic
  • Rule: First term means substitute n = 1 into formula
  • Technique: Calculate 3(1)24=34=1 3(1)^2 - 4 = 3 - 4 = -1
  • Check: Verify by computing second term: 3(2)24=8 3(2)^2 - 4 = 8

Common Mistakes

Avoid these frequent errors
  • Starting with n = 0 instead of n = 1
    Don't substitute n = 0 to find the first term = gives 3(0)² - 4 = -4! This assumes sequences start at position zero, but the first term is at position 1. Always use n = 1 for the first term of a sequence.

Practice Quiz

Test your knowledge with interactive questions

12 ☐ 10 ☐ 8 7 6 5 4 3 2 1

Which numbers are missing from the sequence so that the sequence has a term-to-term rule?

FAQ

Everything you need to know about this question

Why does the first term use n = 1 and not n = 0?

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In most sequences, we count positions starting from 1: first term, second term, third term, etc. Using n = 0 would give you the 'zeroth' term, which doesn't exist in standard sequences!

What if I get a negative number as my answer?

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Negative terms are completely normal in sequences! The formula 3n24 3n^2 - 4 gives -1 for the first term, which is correct. Don't worry about the sign - just follow the math.

How can I check if -1 is really the first term?

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Calculate a few more terms! Second term: 3(2)24=8 3(2)^2 - 4 = 8 , Third term: 3(3)24=23 3(3)^2 - 4 = 23 . The sequence -1, 8, 23... makes sense with increasing values.

Do all quadratic sequences start with negative terms?

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No! It depends on the constant term. Here, we subtract 4, so small values of n give negative results. If the formula was 3n2+1 3n^2 + 1 , all terms would be positive.

What's the difference between 3n² - 4 and other sequence formulas?

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The n2 n^2 term makes this a quadratic sequence - terms increase much faster than linear sequences. The pattern of differences between consecutive terms isn't constant, but the second differences are!

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