Jonathan has 15 pencils and Daniel has 17 pencils.
They decide to give 2 pencils each to their friend Betty.
How many pencils do Jonathan and Daniel have left altogether?
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Jonathan has 15 pencils and Daniel has 17 pencils.
They decide to give 2 pencils each to their friend Betty.
How many pencils do Jonathan and Daniel have left altogether?
To solve this problem, we'll address each part step-by-step and verify at each stage:
Let's proceed through the steps:
Step 1: Jonathan has 15 pencils originally. He gives 2 pencils to Betty. Therefore, his remaining number of pencils is:
Step 2: Daniel has 17 pencils originally. He gives 2 pencils to Betty. Therefore, his remaining number of pencils is:
Step 3: To find the total number of pencils Jonathan and Daniel have left, we add their remaining pencils together:
Therefore, Jonathan and Daniel have altogether pencils left.
If we have 67 blocks in total, how many blocks will remain if we remove 5 tens and 4 ones?
You absolutely can! That's another correct method: . Both approaches give the same answer, so use whichever feels clearer to you.
The process stays the same! Subtract each person's gift from their original amount, then add the remainders. For example: if Jonathan gave 3 and Daniel gave 1, you'd calculate (15-3) + (17-1) = 12 + 16 = 28.
Add up all the pencils at the start and subtract all the pencils given away. Original total: . Total given away: . Remaining: ✓
Not at all! You can calculate Jonathan's remaining pencils first or Daniel's first. Addition is commutative, so 13 + 15 equals 15 + 13. The order doesn't change your final answer.
Follow the same pattern: subtract each person's gift from their original amount, then add all the remainders together. The process scales up perfectly for any number of people!
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