Compare Complex Expressions: (9²-2√81)+4³÷2³ vs (8²+2√64)-3²

Question

Mark the appropriate sign:

(92281)+43:23 —— (82+264)32 (9^2-2\sqrt{81})+4^3:2^3\text{ }\textcolor{red}{_{——\text{ }}}(8^2+2\sqrt{64})-3^2

Video Solution

Solution Steps

00:00 Determine what is the appropriate sign
00:03 We want to calculate each side, let's start from the left
00:10 Let's break down and calculate the power
00:15 Let's break down 81 to 9 squared
00:19 Let's write division as a fraction
00:24 Square root of any number (A) squared cancels out the square
00:27 Let's use this formula in our exercise
00:33 A fraction where numerator and denominator have the same exponent
00:36 The entire fraction can be written with the exponent
00:39 Let's use this formula in our exercise
00:42 Always solve multiplication and division before addition and subtraction
00:45 Let's calculate 4 divided by 2
00:51 Let's continue solving from left to right
00:54 Let's break down and calculate the power
00:59 This is the solution for the left side, now let's calculate the right side
01:11 Let's break down and calculate the power
01:15 Let's break down 64 to 8 squared
01:22 Let's break down and calculate the power
01:27 Always solve parentheses first
01:30 Again let's use the formula where square root cancels square
01:38 Always solve multiplication and division before addition and subtraction
01:42 And this is the solution to the question

Step-by-Step Solution

Let's simplify separately each of the expressions:

a. Let's start with the expression on the left:

(92281)+43:23 (9^2-2\sqrt{81})+4^3:2^3

Note that in this expression the parentheses are meaningless since no mathematical operation is applied to them, therefore we can remove them, while writing the division operation as a fraction:

(92281)+43:23=92281+4323 (9^2-2\sqrt{81})+4^3:2^3=\\ 9^2-2\sqrt{81}+\frac{4^3}{2^3}

Next, we'll notice that the number 4 is a power of the number 2:

4=22 4=2^2

Therefore, we can have all terms with identical bases in the fraction and use the power rule for dividing terms with identical bases:

aman=amn \frac{a^m}{a^n}=a^{m-n}

Let's also remember the power rule for power of a power:

(am)n=amn (a^m)^n=a^{m\cdot n}

And we'll apply these two rules in handling the fraction in the expression mentioned above (which is the third term from the left):

4323=(22)323=22323=2623=263=23=8 \frac{4^3}{2^3} =\frac{(2^2)^3}{2^3} =\frac{2^{2\cdot3}}{2^3} =\frac{2^6}{2^3}=2^{6-3} =2^3=8

Where in the first stage we replaced the number 4 with a power of 2, in the next stage we applied the power rule for power of a power mentioned earlier, and then we simplified the expression in the fraction's numerator and applied the power rule for dividing terms with identical bases, we completed the calculation by simplifying the resulting expression,

Let's return to the complete expression and complete its calculation by substituting what we've gotten so far:

92281+432392281+8=8129+8=8118+8=71 9^2-2\sqrt{81}+\frac{4^3}{2^3} \\ \downarrow\\ 9^2-2\sqrt{81}+8=\\ 81-2\cdot9+8=\\ 81-18+8=71

b. Let's continue with the expression on the right:

(82+264)32 (8^2+2\sqrt{64})-3^2

Here too we notice that the parentheses are meaningless since no mathematical operation is applied to them, therefore, similar to the previous part, we'll remove them:

82+26432 8^2+2\sqrt{64}-3^2

And we'll notice that in this expression there's no special use of power rules therefore we'll continue with direct simplification through numerical calculation only:

82+26432=64+289=64+169=71 8^2+2\sqrt{64}-3^2 =\\ 64+2\cdot8-9=\\ 64+16-9=71

Let's return to the original problem and substitute the results of both solution parts detailed so far in a and b in place of the expressions on the right and left:

(92281)+43:23 —— (82+264)3271 —— 71 (9^2-2\sqrt{81})+4^3:2^3\text{ }\textcolor{red}{_{——\text{ }}}(8^2+2\sqrt{64})-3^2 \\ \downarrow\\ 71\text{ }\textcolor{red}{_{——\text{ }}}71

Therefore it's clear that equality exists, meaning that:

71 = 71 71\text{ }\textcolor{red}{{=\text{ }}}71

Therefore the correct answer is answer c.

Answer

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