Two lines haves slopes of -3 and -6.
Which of the lines forms a greater angle with the x axis?
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Two lines haves slopes of -3 and -6.
Which of the lines forms a greater angle with the x axis?
To find which line forms a greater angle with the x-axis, we use the formula . This gives us the angles formed by lines with slopes and .
We first calculate the inverse tangent for both slopes:
The greater the absolute value of the negative slope, the closer the line is to the vertical, thus forming a greater angle with the x-axis.
Comparing and , we see that has a greater absolute value, indicating a steeper angle. Hence, although is steeper, it forms a smaller angle with the x-axis because we're considering angles formed in the positive x-direction (i.e., above the x-axis).
Therefore, the line whose slope is forms the greater angle with the x-axis.
The line whose slope is -3 forms the greater angle.
The line whose slope is -3 forms the greater angle.
Look at the function shown in the figure.
When is the function positive?
Think about it visually! A line with slope -6 is steeper (more vertical) than slope -3. When we measure the positive angle from the x-axis, steeper negative slopes create smaller acute angles.
Use your calculator: and . The absolute values show that 71.57° > 80.54° is false, so 71.57° is actually the larger positive angle!
It's the acute angle between the line and the positive x-axis, measured counterclockwise. For negative slopes, we consider the positive equivalent of this angle.
No! You must use the inverse tangent function or think about absolute values. Comparing -3 and -6 directly gives the wrong relationship for angles.
Because we're looking at the magnitude of the angle, not its direction. The absolute value , but this means slope -3 creates a larger positive angle with the x-axis.
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