Compare Mixed Numbers with 1/8: Sorting 10%, 20%, 11/80, and More

The problem requires us to organize values into two groups based on whether they are smaller or larger than $\frac{1}{8}$, which equals $0.125$.

First, convert the percentages to decimal form:

• $10\% = 0.10$

• $20\% = 0.20$

Now convert the fractions to decimal form:

• $\frac{11}{80} = 0.1375$

• $\frac{97}{800} = 0.12125$

The decimal $0.15$ is already given in decimal form.

We compare all values to $0.125$ (which is $\frac{1}{8}$):

• 0.10 < 0.125

• 0.20 > 0.125

• 0.1375 > 0.125

• 0.12125 < 0.125

• 0.15 > 0.125

Thus, we have:

Values smaller than $\frac{1}{8}$: $10\%$ and $\frac{97}{800}$.

Values larger than $\frac{1}{8}$: $20\%$, $\frac{11}{80}$, and $0.15$.

The correct grouping matches choice 1:
10\%, \frac{97}{800} < \frac{1}{8}
20\%, \frac{11}{80}, 0.15 > \frac{1}{8}