Complete the numbers to obtain a number divisible by 2 without remainder.
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Complete the numbers to obtain a number divisible by 2 without remainder.
To solve this problem, we need to ensure that the complete number is divisible by 2. According to the rules of divisibility for 2, a number is divisible by 2 if its last digit is even. Therefore, we need to select a digit to replace the blank that will result in an even number when appended to 214.
Let's evaluate the provided choices:
Based on these evaluations, all individual choices result in a number that is divisible by 2.
Therefore, the correct answer is: All answers are correct.
All answers are correct
Is the number 43 divisible by 4?
The divisibility rule for 2 is based on place value! Since every place value position except the units place represents an even number of something (tens, hundreds, etc.), only the units digit determines if the whole number is even or odd.
Even digits are 0, 2, 4, 6, and 8. These digits can be divided by 2 with no remainder. Odd digits are 1, 3, 5, 7, and 9.
Yes! Any even digit that completes the number will make it divisible by 2. In this case, 4, 6, and 8 all work, so all answers are correct.
Simply look at the last digit of your completed number. If it's 0, 2, 4, 6, or 8, then the number is divisible by 2. No calculation needed!
For divisibility by 5, the number must end in 0 or 5. Each divisibility rule has its own pattern - that's why it's important to memorize the key ones!
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