Divisibility Challenge: Find Missing Digits for 51— to Be Divisible by 10

Complete the number so that it is divisible by 10 without a remainder:

51 — — 51\text{ }_{—\text{ —}}

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Step-by-step video solution

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00:00 Complete the digits so that the number is divisible by 10
00:04 A number divisible by 10 is a number with 0 as its units digit
00:10 According to this method, we will go through all numbers and eliminate accordingly
00:21 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

Complete the number so that it is divisible by 10 without a remainder:

51 — — 51\text{ }_{—\text{ —}}

2

Step-by-step solution

To solve this problem, we'll focus on ensuring divisibility by 10 for the given number 51 — — 51\text{ }_{—\text{ —}} .

The divisibility rule for 10 states that a number must end with the digit 0 to be divisible by 10.

Thus, the missing digits should form a number that ends in 0. Given the partial number 51 1 — 51\text{ }_{1\text{ —}} , we need to check potential combinations that satisfy this rule.

  • Evaluation of the required final digit: Only the digit 0 satisfies the condition for divisibility by 10, meaning the complete number should be 51y0 51y0 where y y is any digit.

Hence, the missing sequence to ensure divisibility by 10 is 1,0 1, 0 . Therefore, 51 1 0 51\text{ }_{1\text{ }0} is the solution.

Returning to the choices provided, the correct answer is choice 1: 1,0 1, 0 .

To conclude, the number is completed as 5110 5110 , which is divisible by 10.

3

Final Answer

1, 0

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Is the number 43 divisible by 4?

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