Complete the Expression: Finding (4×a)^(2b) in Exponential Form

Insert the corresponding expression:

(4×a)2b= \left(4\times a\right)^{2b}=

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1

Understand the problem

Insert the corresponding expression:

(4×a)2b= \left(4\times a\right)^{2b}=

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the structure and components of the initial expression
  • Step 2: Apply the inverse power of a power rule
  • Step 3: Find the matching choice among the given options

Now, let's work through each step:

Step 1: The given expression is (4×a)2b\left(4 \times a\right)^{2b}. This indicates that the base (4×a)\left(4 \times a\right) is raised to the power of 2b2b.

Step 2: By the inverse power of a power property, we rewrite (4×a)2b\left(4 \times a\right)^{2b} in a way that exposes it as a power raised to a power. The expression (xmn)(x^{m \cdot n}) equates to (xm)n(x^m)^n. Hence, we can rewrite (4×a)2b\left(4 \times a\right)^{2b} as ((4×a)2)b\left(\left(4 \times a\right)^2\right)^b.

Step 3: The correct answer from the provided choices matches choice 1: ((4×a)2)b\left(\left(4 \times a\right)^2\right)^b.

Therefore, applying the inverse power of a power rule, the expression (4×a)2b\left(4 \times a\right)^{2b} becomes ((4×a)2)b\left(\left(4 \times a\right)^2\right)^b.

3

Final Answer

((4×a)2)b \left(\left(4\times a\right)^2\right)^b

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\( 112^0=\text{?} \)

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