Complete the Expression: Finding (4×a)^(2b) in Exponential Form

Power of a Power with Variable Bases

Insert the corresponding expression:

(4×a)2b= \left(4\times a\right)^{2b}=

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1

Understand the problem

Insert the corresponding expression:

(4×a)2b= \left(4\times a\right)^{2b}=

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the structure and components of the initial expression
  • Step 2: Apply the inverse power of a power rule
  • Step 3: Find the matching choice among the given options

Now, let's work through each step:

Step 1: The given expression is (4×a)2b\left(4 \times a\right)^{2b}. This indicates that the base (4×a)\left(4 \times a\right) is raised to the power of 2b2b.

Step 2: By the inverse power of a power property, we rewrite (4×a)2b\left(4 \times a\right)^{2b} in a way that exposes it as a power raised to a power. The expression (xmn)(x^{m \cdot n}) equates to (xm)n(x^m)^n. Hence, we can rewrite (4×a)2b\left(4 \times a\right)^{2b} as ((4×a)2)b\left(\left(4 \times a\right)^2\right)^b.

Step 3: The correct answer from the provided choices matches choice 1: ((4×a)2)b\left(\left(4 \times a\right)^2\right)^b.

Therefore, applying the inverse power of a power rule, the expression (4×a)2b\left(4 \times a\right)^{2b} becomes ((4×a)2)b\left(\left(4 \times a\right)^2\right)^b.

3

Final Answer

((4×a)2)b \left(\left(4\times a\right)^2\right)^b

Key Points to Remember

Essential concepts to master this topic
  • Rule: Use power of a power property: (xm)n=xmn (x^m)^n = x^{mn}
  • Technique: Rewrite (4a)2b (4a)^{2b} as ((4a)2)b ((4a)^2)^b by factoring exponent
  • Check: Verify both expressions equal same value when substituting test values ✓

Common Mistakes

Avoid these frequent errors
  • Applying exponent rules incorrectly to the base and exponent separately
    Don't split (4a)2b (4a)^{2b} into 42b×a2b 4^{2b} \times a^{2b} = wrong application of power rules! This confuses the order of operations and misapplies exponent properties. Always treat the entire base as one unit when applying the power of a power rule.

Practice Quiz

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\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why can't I just distribute the exponent 2b to each part?

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The base (4×a) (4 \times a) is treated as one complete unit. You can only distribute exponents when you have multiplication inside parentheses after applying power rules correctly.

How do I know which way to rewrite the expression?

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Look for ways to factor the exponent. Since 2b=2×b 2b = 2 \times b , you can rewrite (4a)2b (4a)^{2b} as ((4a)2)b ((4a)^2)^b using the power of a power rule.

What's the difference between the correct and incorrect answer choices?

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The correct answer ((4a)2)b ((4a)^2)^b shows nested exponents. Wrong choices like (4a)2(4a)b (4a)^2(4a)^b represent multiplication of powers, which is completely different!

Can I check my answer by expanding both expressions?

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Yes! Both (4a)2b (4a)^{2b} and ((4a)2)b ((4a)^2)^b should give the same result when you substitute specific values for a and b.

Why is this called the 'inverse' power of a power rule?

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It's working backwards from the usual power of a power rule. Instead of simplifying (xm)n (x^m)^n to xmn x^{mn} , we're breaking xmn x^{mn} back into (xm)n (x^m)^n form.

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