Power of a power basic examples
Example 1
(43)2=
We can see that the exponent 2 applies to the entire expression 43.
therefore, we can multiply both exponents and raise the base to the result of the multiplication.
We will obtain:
43Γ2=46=4096
If we were presented with an exercise in which there is a certain power over a term that already has another power, we will multiply the powers that have equal bases.
Example 2
Let's start with an easy one:
(X6β3)4=
We'll see that there is a subtraction in the exponents of X and that, first, we must deal with it.
We'll do this and obtain:
(X3)4=
Now we can apply the power of a power property and multiply the exponents, we will obtain:
X12
Good. Let's move on to a more complicated example:
Example 3
(X2X2β)4β
(Y4Y2β)3=
Recommendation:
Before applying the power located outside the parentheses to each of the terms separately, first, it is advisable to carefully observe the exercise.
Upon observing it, you will realize that you can reduce or subtract exponents from the fractions themselves, before touching the exponent located outside the parentheses.
We will subtract the exponents of the corresponding bases (we will reduce) and obtain:
(2X)4β
(4Y)3=
Now we can apply the exponent to each of the terms separately (do not forget about the coefficients) and we will get:
16X4β
64Y3=
We can try to find a common term to better organize the exercise and we will obtain:
16(X4β
4Y3)
Perfect! Now, let's move on to a complex and slightly different example:
Power of a power advanced examples:
Example 4
(2X+3)Xβ
(2X)4=
Don't worry, even if there are mathematical operations among the exponents, the properties do not change.
Let's start with the first expression which is a bit more complex. We learned that, when we have a power of a power we multiply the exponents.
We will multiply the entire exponent that is inside the parentheses by the entire exponent located outside the parentheses. We will do the same with the other term and we will obtain:
2(X+3)β
Xβ
24X=
We will multiply the exponents of the first expression and we will obtain:
2X2+3Xβ
24X=
Now let's remember that, if we have a multiplication operation between equal bases we can add the exponents.
We will do this and we will obtain:
2X2+3X+4X=
We simplify terms in the exponent and it will give us:
2X2+7X=
Example 5
Simplify the following expression:
(2xy2)3(3x3y2)2(2x2y4)4β
To simplify the expression, first apply the power of a product property, which allows us to raise each of the factors inside the parenthesis to the indicated power, then apply the power of a power property. We obtain:
23(x)3(y2)3(32(x3)2(y2)2)β
(24(x2)4(y4)4)β=8x3y6(9x6y4)β
(16x8y16)β
Finally, apply the properties of products and quotients of powers with the same base:
8x3y6144x6+8y4+16β=8x3y6114x14y20β=18x14β3y20β6=18x11y14
If you are interested in this article, you might also be interested in the following articles:
- Powers
- The Rules of Exponentiation
- Division of Powers with the Same Base
- Power of a Multiplication
- Power of a Quotient
- Power with Zero Exponent
- Powers with a Negative Integer Exponent
- Taking Advantage of All the Properties of Powers or Laws of Exponents
- Exponentiation of Whole Numbers
In the Tutorela blog, you will find a variety of articles about mathematics.
Exercises on Power of a Power
Basic Exercises of Power of a Power:
(42)2=
(33)2=
(22)2=
(52)5=
(72)2=
Exercises of Power of a Power:
(X2β4)2=
(X2+4)3=
(X21β7)2=
(X11β9)3=
(X5β3)3=
Intermediate Level Power of a Power Exercises
(X4X5β)2β
(Y3Y3β)3=
(2Y4Y5β)2β
(2YY4β)4=
(2X2X5β)3β
(2XX3β)3=
(2Y52Y5β)3β
(2X3X3β)3=
(2Y52Y5β)3β
(2X3X3β)3β
(2Y62Y3β)2β
(2X2X2β)2=
Advanced Level Power of a Power Exercises
(3X+7)Xβ
(3X)3=
(2Xβ2)Xβ
(3Xβ2)6=
(3Xβ3)Xβ
(3Xβ3)3=
(32β3)2β
(7Xβ5)2=
(8Xβ3)Xβ
(72X+2)X=
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Review Questions
What is a power of a power?
A power of a power is an expression in which we raise a power to another power.
What is a power of a power and example?
A power of a power is a power in which the base is also a power, for example:
- (32)5
- (52x+1)2
How do you calculate a power of a power?
To solve a power of a power, we must multiply the exponents, and the result of the multiplication is placed as the exponent on the initial base.
Exercises on Power of a Power
Exercise 1
Assignment
23Γ24+(43)2+2325β=
Solution
23β
24+(43)2+2325β=
23+4+43β
2+2(5β3)=
27+46+22
Answer
22+27+46
Do you know what the answer is?
Exercise 2
Assignment
(4x)y=
Solution
(4x)y=4xβ
y
Answer
4xy
Exercise 3
Assignment
(22)3+(33)4+(92)6=
Solution
We will use the formula
(am)n=amβ
n
22β
3+33β
4β
92β
6=
26+312β
912
Answer
26+312+912
Exercise 4
Assignment
(42)3+(g3)4=
Solution
We will use the formula
(am)n=amβ
n
42β
3+93β
4=
46+912
Answer
46+912
Exercise 5
Assignment
((7Γ3)2)6+(3β1)3Γ(23)4=
Solution
We will use the formula
(am)n=amβ
n
(7β
3)2β
6+3β1β
3β
23β
4=
2112+3β3β
212
Answer
2112+3β3β
212
Do you think you will be able to solve it?