Power of a Power

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Power of a Power

When we have an expression raised to a power that, in turn, is raised (within parentheses) to another power, we can multiply the exponents and raise the base number to the result of this multiplication.

Formula of the property

(an)m=a(n×m) (a^n)^m=a^{(n\times m)}
This property is also concerning algebraic expressions.

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Test yourself on power of a power!

Insert the corresponding expression:

\( \left(10^3\right)^3= \)

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A - When there is a power inside parentheses.

Power of a power basic examples

Example 1

(43)2=(4^3 )^2=
We can see that the exponent 2 2 applies to the entire expression 43 4^3 .
therefore, we can multiply both exponents and raise the base to the result of the multiplication.
We will obtain:
43×2=46=4096 4^{3\times2}=4^6=4096


If we were presented with an exercise in which there is a certain power over a term that already has another power, we will multiply the powers that have equal bases.

Example 2

Let's start with an easy one:

(X63)4= (X^{6-3})^4=

We'll see that there is a subtraction in the exponents of X X and that, first, we must deal with it.

We'll do this and obtain:

(X3)4= (X^3)^4=

Now we can apply the power of a power property and multiply the exponents, we will obtain:

X12 X^{12}


Good. Let's move on to a more complicated example:

Example 3

(2X2X)4(4Y2Y)3= (\frac{2X^2}{X})^4\cdot(\frac{4Y^2}{Y})^3=

Recommendation:

Before applying the power located outside the parentheses to each of the terms separately, first, it is advisable to carefully observe the exercise.

Upon observing it, you will realize that you can reduce or subtract exponents from the fractions themselves, before touching the exponent located outside the parentheses.

We will subtract the exponents of the corresponding bases (we will reduce) and obtain:

(2X)4(4Y)3= (2X)^4\cdot(4Y)^3=

Now we can apply the exponent to each of the terms separately (do not forget about the coefficients) and we will get:

16X464Y3= 16X^4\cdot64Y^3=

We can try to find a common term to better organize the exercise and we will obtain:

16(X44Y3) 16(X^4\cdot4Y^3)


Perfect! Now, let's move on to a complex and slightly different example:

Power of a power advanced examples:

Example 4

(2X+3)X(2X)4= (2^{X+3})^X\cdot(2^X)^4=

Don't worry, even if there are mathematical operations among the exponents, the properties do not change.

Let's start with the first expression which is a bit more complex. We learned that, when we have a power of a power we multiply the exponents.

We will multiply the entire exponent that is inside the parentheses by the entire exponent located outside the parentheses. We will do the same with the other term and we will obtain:

2(X+3)X24X= 2^{(X+3)\cdot X}\cdot2^{4X}=

We will multiply the exponents of the first expression and we will obtain:

2X2+3X24X= 2^{X^2+3X}\cdot2^{4X}=

Now let's remember that, if we have a multiplication operation between equal bases we can add the exponents.

We will do this and we will obtain:

2X2+3X+4X= 2^{X^2+3X+4X}=

We simplify terms in the exponent and it will give us:

2X2+7X= 2^{X^2+7X}=


Example 5

Simplify the following expression:

(3x3y2)2(2x2y4)4(2xy2)3 \frac{\left(3x^3y^2\right)^2\left(2x^2y^4\right)^4}{\left(2xy^2\right)^3}

To simplify the expression, first apply the power of a product property, which allows us to raise each of the factors inside the parenthesis to the indicated power, then apply the power of a power property. We obtain:

(32(x3)2(y2)2)(24(x2)4(y4)4)23(x)3(y2)3=(9x6y4)(16x8y16)8x3y6 \frac{\left(3^2\left(x^3\right)^2\left(y^2\right)^2\right)\cdot\left(2^4\left(x^2\right)^4\left(y^4\right)^4\right)}{2^3\left(x^{}\right)^3\left(y^2\right)^3}=\frac{\left(9x^6y^4\right)\cdot\left(16x^8y^{16}\right)}{8x^3y^6}

Finally, apply the properties of products and quotients of powers with the same base:

144x6+8y4+168x3y6=114x14y208x3y6=18x143y206=18x11y14 \frac{144x^{6+8}y^{4+16}}{8x^3y^6}=\frac{114x^{14}y^{20}}{8x^3y^6}=18x^{14-3}y^{20-6}=18x^{11}y^{14}


Exercises on Power of a Power

Basic Exercises of Power of a Power:

(42)2= \left(4^2\right)^2=

(33)2= \left(3^3\right)^2=

(22)2= \left(2^2\right)^2=

(52)5= \left(5^2\right)^5=

(72)2= \left(7^2\right)^2=


Exercises of Power of a Power:

(X24)2= \left(X^{2-4}\right)^2=

(X2+4)3= \left(X^{2+4}\right)^3=

(X217)2= \left(X^{21-7}\right)^2=

(X119)3= \left(X^{11-9}\right)^3=

(X53)3= \left(X^{5-3}\right)^3=


Intermediate Level Power of a Power Exercises

(4X5X)2(3Y3Y)3= (\frac{4X^5}{X})^2\cdot(\frac{3Y^3}{Y})^3=

(4Y52Y)2(Y42Y)4= (\frac{4Y^5}{2Y})^2\cdot(\frac{Y^4}{2Y})^4=

(2X52X)3(X32X)3= (\frac{2X^5}{2X})^3\cdot(\frac{X^3}{2X})^3=

(2Y52Y5)3(X32X3)3= (\frac{2Y^5}{2Y^5})^3\cdot(\frac{X^3}{2X^3})^3=

(2Y52Y5)3(X32X3)3(2Y32Y6)2(X22X2)2= (\frac{2Y^5}{2Y^5})^3\cdot(\frac{X^3}{2X^3})^3\cdot(\frac{2Y^3}{2Y^6})^2\cdot(\frac{X^2}{2X^2})^2=


Advanced Level Power of a Power Exercises

(3X+7)X(3X)3= (3^{X+7})^X\cdot(3^X)^3=

(2X2)X(3X2)6= (2^{X-2})^X\cdot(3^{X-2})^6=

(3X3)X(3X3)3= (3^{X-3})^X\cdot(3^{X-3})^3=

(323)2(7X5)2= (3^{2-3})^2\cdot(7^{X-5})^2=

(8X3)X(72X+2)X= (8^{X-3})^X\cdot(72^{X+2})^X=


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Review Questions

What is a power of a power?

A power of a power is an expression in which we raise a power to another power.

What is a power of a power and example?

A power of a power is a power in which the base is also a power, for example:

  • (32)5 \left(3^2\right)^5
  • (52x+1)2 \left(5^{2x+1}\right)^2

How do you calculate a power of a power?

To solve a power of a power, we must multiply the exponents, and the result of the multiplication is placed as the exponent on the initial base.


Exercises on Power of a Power

Exercise 1

Assignment

23×24+(43)2+2523= 2^3\times2^4+(4^3)^2+\frac{2^5}{2^3}=

Solution

2324+(43)2+2523= 2^3\cdot2^4+\left(4^3\right)^2+\frac{2^5}{2^3}=

23+4+432+2(53)= 2^{3+4}+4^{3\cdot2}+2^{\left(5-3\right)}=

27+46+22 2^7+4^6+2^2

Answer

22+27+46 2^2+2^7+4^6


Do you know what the answer is?

Exercise 2

Assignment

(4x)y= (4^x)^y=

Solution

(4x)y=4xy \left(4^x\right)^y=4^{x\cdot y}

Answer

4xy 4^{xy}


Exercise 3

Assignment

(22)3+(33)4+(92)6= (2^2)^3+(3^3)^4+(9^2)^6=

Solution

We will use the formula

(am)n=amn \left(a^m\right)^n=a^{m\cdot n}

223+334926= 2^{2\cdot3}+3^{3\cdot4}\cdot9^{2\cdot6}=

26+312912 2^6+3^{12}\cdot9^{12}

Answer

26+312+912 2^6+3^{12}+9^{12}


Check your understanding

Exercise 4

Assignment

(42)3+(g3)4= (4^2)^3+(g^3)^4=

Solution

We will use the formula

(am)n=amn \left(a^m\right)^n=a^{m\cdot n}

423+934= 4^{2\cdot3}+9^{3\cdot4}=

46+912 4^6+9^{12}

Answer

46+912 4^6+9^{12}


Exercise 5

Assignment

((7×3)2)6+(31)3×(23)4= ((7\times3)^2)^6+(3^{-1})^3\times(2^3)^4=

Solution

We will use the formula

(am)n=amn \left(a^m\right)^n=a^{m\cdot n}

(73)26+313234= (7\cdot3)^{2\cdot6}+3^{-1\cdot3}\cdot2^{3\cdot4}=

2112+33212 21^{12}+3^{-3}\cdot2^{12}

Answer

2112+33212 21^{12}+3^{-3}\cdot2^{12}


Do you think you will be able to solve it?

Examples with solutions for Power of a Power

Exercise #1

Insert the corresponding expression:

(103)3= \left(10^3\right)^3=

Video Solution

Step-by-Step Solution

To solve this problem, we will proceed with the following steps:

  • Identify the expression structure.
  • Apply the power of a power rule for exponents.
  • Simplify the expression.

Now, let's work through each step in detail:

Step 1: Identify the expression structure.
We have the expression (103)3(10^3)^3. This indicates a power of a power where the base is 10, the inner exponent is 3, and the entire expression is raised to another power of 3.

Step 2: Apply the power of a power rule.
The rule states (am)n=am×n(a^m)^n = a^{m \times n}. Applying this to our specific expression gives us:

(103)3=103×3\left(10^3\right)^3 = 10^{3 \times 3}

Step 3: Perform the multiplication in the exponent.
Calculating 3×33 \times 3, we get 99. Thus, the expression simplifies to:

10910^9

Therefore, the solution to the problem is:

103×3\boxed{10^{3 \times 3}}

Examining the provided choices:

  • Choice 1: 103+310^{3+3} - Incorrect, because it uses addition instead of multiplication.
  • Choice 2: 103×310^{3 \times 3} - Correct, as it matches our derived expression.
  • Choice 3: 103310^{\frac{3}{3}} - Incorrect, because it uses division instead of multiplication.
  • Choice 4: 103310^{3-3} - Incorrect, because it uses subtraction instead of multiplication.

The correct answer is 103×310^{3 \times 3}, which is represented by Choice 2.

Answer

103×3 10^{3\times3}

Exercise #2

Insert the corresponding expression:

(128)4= \left(12^8\right)^4=

Video Solution

Step-by-Step Solution

To solve this problem, we will use the Power of a Power rule of exponents, which simplifies expressions where an exponent is raised to another power. The rule is expressed as:

(am)n=amn(a^m)^n = a^{m \cdot n}

Now, let’s apply this rule to the given problem:

(128)4(12^8)^4

Step-by-step solution:

  • Identify the base and exponents: In this case, the base is 12, with the first exponent being 8 and the second exponent being 4.
  • Apply the Power of a Power rule by multiplying the exponents: (8)(4)=32(8) \cdot (4) = 32.
  • Replace the original expression with the new exponent: (128)4=1232(12^8)^4 = 12^{32}.

Therefore, the simplified expression is 1232\mathbf{12^{32}}.

Let's compare the answer with the given choices:

  • Choice 1: 12412^4 - Incorrect, uses incorrect exponent rule.
  • Choice 2: 121212^{12} - Incorrect, uses incorrect exponent multiplication.
  • Choice 3: 12212^2 - Incorrect, unrelated solution.
  • Choice 4: 123212^{32} - Correct, matches our calculation.

Thus, the correct choice is Choice 4: 123212^{32}.

Therefore, the expression (128)4(12^8)^4 simplifies to 123212^{32}, confirming the correct choice is indeed Choice 4.

Answer

1232 12^{32}

Exercise #3

Insert the corresponding expression:

(166)7= \left(16^6\right)^7=

Video Solution

Step-by-Step Solution

To solve the expression (166)7(16^6)^7, we will use the power of a power rule for exponents. This rule states that when you raise a power to another power, you multiply the exponents. Here are the steps:

  • Identify the components: The base is 16, and the inner exponent is 6. The outer exponent is 7.
  • Apply the power of a power rule: According to the rule, (am)n=amn(a^m)^n = a^{m \cdot n}. Thus, (166)7=1667(16^6)^7 = 16^{6 \cdot 7}.
  • Multiply the exponents: Calculate the product of the exponents 6×76 \times 7. This gives us 42.
  • Rewrite the expression: Substitute the product back into the expression, giving us 164216^{42}.

Therefore, the simplified expression is 1642\mathbf{16^{42}}.

Checking against the answer choices, we find:
1. 164216^{42} is given as choice 1.
2. Other choices do not match the simplified expression.
Choice 1 is correct because it accurately reflects the application of exponent rules.

Consequently, we conclude that the correct solution is 1642\mathbf{16^{42}}.

Answer

1642 16^{42}

Exercise #4

Insert the corresponding expression:

(27)5= \left(2^7\right)^5=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the given information.
  • Step 2: Apply the appropriate exponent rule.
  • Step 3: Perform the necessary calculations.

Let's work through each step:

Step 1: The given expression is (27)5 \left(2^7\right)^5 . Here, the base is 2 2 , and we have two exponents: 7 7 in the inner expression and 5 5 outside.

Step 2: We'll use the power of a power rule for exponents, which states (am)n=amn (a^m)^n = a^{m \cdot n} . This means we will multiply the exponents 7 7 and 5 5 .

Step 3: Calculating, we multiply the exponents:
7×5=35 7 \times 5 = 35

Therefore, the expression (27)5 \left(2^7\right)^5 simplifies to 235 2^{35} .

Now, let's verify with the given answer choices:

  • Choice 1: 212 2^{12} - Incorrect, as the exponents were not multiplied properly.
  • Choice 2: 22 2^2 - Incorrect, as it significantly underestimates the combined exponent value.
  • Choice 3: 235 2^{35} - Correct, matches the calculated exponent.
  • Choice 4: 257 2^{\frac{5}{7}} - Incorrect, involves incorrect fraction of exponents.

Thus, the correct choice is Choice 3: 235 2^{35} .

I am confident in the correctness of this solution as it directly applies well-established exponent rules.

Answer

235 2^{35}

Exercise #5

Insert the corresponding expression:

(22)3= \left(2^2\right)^3=

Video Solution

Step-by-Step Solution

We are given the expression (22)3 (2^2)^3 and need to simplify it using the laws of exponents and identify the corresponding expression among the choices.

To simplify the expression (22)3 (2^2)^3 , we use the "power of a power" rule, which states that (am)n=am×n(a^m)^n = a^{m \times n}.

Applying this rule to our expression, we have:

(22)3=22×3(2^2)^3 = 2^{2 \times 3}

Calculating the new exponent:

2×3=62 \times 3 = 6

Thus, the expression simplifies to:

262^6

Now, let's compare our result 262^6 with the given choices:

  • Choice 1: 22+3=252^{2+3} = 2^5 - Incorrect, as our expression evaluates to 262^6, not 252^5.
  • Choice 2: 223=212^{2-3} = 2^{-1} - Incorrect, as our expression evaluates to 262^6, not 212^{-1}.
  • Choice 3: 2232^{\frac{2}{3}} - Incorrect, as our expression evaluates to 262^6, not a fractional exponent expression.
  • Choice 4: 22×3=262^{2 \times 3} = 2^6 - Correct, as this matches our simplified expression.

Therefore, the correct choice is Choice 4: 22×32^{2 \times 3}.

Answer

22×3 2^{2\times3}

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