Complete the Number: Make 54216_ Divisible by 4

Complete the number so that it is divisible by 4 without a remainder:

54216  54216\text{ }_—

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Step-by-step video solution

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00:00 Complete the digit so that the number is divisible by 4
00:03 Multiply the tens digit by 2, and add the ones digit to it
00:07 If this number is divisible by 4, then the number itself is divisible by 4
00:12 According to this method, we will go through all numbers and eliminate accordingly
00:53 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

Complete the number so that it is divisible by 4 without a remainder:

54216  54216\text{ }_—

2

Step-by-step solution

To solve this problem, we need to complete the number 54216_54216\_ so that the entire number is divisible by 4. The rule for divisibility by 4 is that the number formed by its last two digits must be divisible by 4.

Let's try each of the given possibilities for the missing digit:

  • For 0: Make the number 542160542160. Last two digits are 60. Check divisibility: 60÷4=1560 \div 4 = 15, remainder 0.
  • For 1: Make the number 542161542161. Last two digits are 61. Check divisibility: 61÷4=15.2561 \div 4 = 15.25, remainder is not 0.
  • For 2: Make the number 542162542162. Last two digits are 62. Check divisibility: 62÷4=15.562 \div 4 = 15.5, remainder is not 0.
  • For 3: Make the number 542163542163. Last two digits are 63. Check divisibility: 63÷4=15.7563 \div 4 = 15.75, remainder is not 0.

Out of the available options, only appending 0 to make the number 542160542160 satisfies the condition, as 60 is divisible by 4.

Therefore, the digit that should replace the missing underscore to make the number divisible by 4 is 0.

3

Final Answer

0

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Is the number 43 divisible by 4?

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