Complete the number so that it is divisible by 4 without a remainder:
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Complete the number so that it is divisible by 4 without a remainder:
To solve this problem, we need to complete the number so that the entire number is divisible by 4. The rule for divisibility by 4 is that the number formed by its last two digits must be divisible by 4.
Let's try each of the given possibilities for the missing digit:
Out of the available options, only appending 0 to make the number satisfies the condition, as 60 is divisible by 4.
Therefore, the digit that should replace the missing underscore to make the number divisible by 4 is 0.
0
Is the number 10 divisible by 4?
This is the divisibility rule for 4! Since 100 is divisible by 4, any hundreds, thousands, or higher place values won't affect divisibility. Only the last two digits matter.
Treat it as a two-digit number with a leading zero! For example, if the last digits are '05', check if has remainder 0 (it doesn't).
Similar rules exist! For divisibility by 8, check the last three digits. Each rule is designed based on powers of 10 and the divisor.
In this problem, we're limited to the given options (0, 1, 2, 3). But mathematically, any digit could potentially work - like 4 would give us 64, which is also divisible by 4!
Memorize some patterns! Numbers ending in 00, 04, 08, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96 are all divisible by 4.
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