Complete the number so that it is divisible by 4 without a remainder:
Complete the number so that it is divisible by 4 without a remainder:
To solve this problem, we'll follow these steps:
Step 1: Identify the rule for divisibility by 4.
Step 2: Apply this rule to the number .
Step 3: Test each possible digit for the missing number to find a two-digit number divisible by 4.
Now, let's work through each step:
Step 1: The divisibility rule for 4 is that a number is divisible by 4 if the last two digits form a number divisible by 4.
Step 2: In the number , the last two digits are _{\—\text{ }}2. We want this two-digit number to be divisible by 4.
Step 3: Test the potential digits for blank using the choices given:
If the blank is 0, the last two digits are 02, which is divisible by 4. But this isn't provided as a solution in the context.
If the blank is 2, the last two digits are 22, which is not divisible by 4.
If the blank is 3, the last two digits are 32, which is divisible by 4.
If the blank is 4, the last two digits are 42, which is not divisible by 4.
Checking through these options shows that placing a 3 in the blank makes the number divisible by 4.
Therefore, the solution to the problem is .
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