Complete the Perfect Square: Solve (x-?)² = x²-?+25

Question

Fill in the blanks:

(x?)2=x2?+25 (x-?)^2=x^2-?+25

Video Solution

Solution Steps

00:00 Complete the missing
00:03 Use the shortened multiplication formulas to open the parentheses
00:06 Let's substitute A as the unknown
00:14 Let's equate the equal coefficients
00:18 Let's extract the root and find A
00:21 Let's substitute A and solve
00:34 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Recognize this as a binomial square problem.
  • Step 2: Identify the expanded form of a binomial square.
  • Step 3: Match the terms from both sides of the equation.

Now, let's work through each step:
Step 1: The given expression (x?)2=x2?+25(x-?)^2 = x^2 - ? + 25 is the expansion of a binomial (xa)2 (x-a)^2 .
Step 2: Recall that (xa)2=x22ax+a2(x-a)^2 = x^2 - 2ax + a^2.
Step 3: Compare this equivalent form to x2?+25x^2 - ? + 25:

- The term x2x^2 matches directly on both sides.
- The constant term a2=25a^2 = 25, so a=5a = 5 because 52=255^2 = 25.
- The middle term 2ax-2ax is currently unspecified, but it provides the form needed to fill the blank with 2ax-2ax.

Matching the expanded form: - The term inside (x?)(x-?) should be 55 (because a=5a=5).
- Therefore, the missing linear term can be 10x10x since 2×5=10-2 \times 5 = -10.

Therefore, the solution to the problem is 5, 10x5,\text{ }10x.

Answer

5, 10x 5,\text{ }10x