Complete the Perfect Square: Solve (x-?)² = x²-?+25

Perfect Square Trinomials with Missing Terms

Fill in the blanks:

(x?)2=x2?+25 (x-?)^2=x^2-?+25

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Complete the missing
00:03 Use the shortened multiplication formulas to open the parentheses
00:06 Let's substitute A as the unknown
00:14 Let's equate the equal coefficients
00:18 Let's extract the root and find A
00:21 Let's substitute A and solve
00:34 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Fill in the blanks:

(x?)2=x2?+25 (x-?)^2=x^2-?+25

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Recognize this as a binomial square problem.
  • Step 2: Identify the expanded form of a binomial square.
  • Step 3: Match the terms from both sides of the equation.

Now, let's work through each step:
Step 1: The given expression (x?)2=x2?+25(x-?)^2 = x^2 - ? + 25 is the expansion of a binomial (xa)2 (x-a)^2 .
Step 2: Recall that (xa)2=x22ax+a2(x-a)^2 = x^2 - 2ax + a^2.
Step 3: Compare this equivalent form to x2?+25x^2 - ? + 25:

- The term x2x^2 matches directly on both sides.
- The constant term a2=25a^2 = 25, so a=5a = 5 because 52=255^2 = 25.
- The middle term 2ax-2ax is currently unspecified, but it provides the form needed to fill the blank with 2ax-2ax.

Matching the expanded form: - The term inside (x?)(x-?) should be 55 (because a=5a=5).
- Therefore, the missing linear term can be 10x10x since 2×5=10-2 \times 5 = -10.

Therefore, the solution to the problem is 5, 10x5,\text{ }10x.

3

Final Answer

5, 10x 5,\text{ }10x

Key Points to Remember

Essential concepts to master this topic
  • Formula: (xa)2=x22ax+a2 (x-a)^2 = x^2 - 2ax + a^2 for any value a
  • Technique: From constant term 25, find a=25=5 a = \sqrt{25} = 5 , then middle term is 2(5)x=10x -2(5)x = -10x
  • Check: Expand (x5)2=x210x+25 (x-5)^2 = x^2 - 10x + 25 matches the given form ✓

Common Mistakes

Avoid these frequent errors
  • Taking the negative square root for the constant term
    Don't assume the first blank is -5 just because you see a minus sign = wrong expansion! The minus sign is part of the binomial form (x-a)², not the value of a itself. Always take the positive square root of the constant term to find a.

Practice Quiz

Test your knowledge with interactive questions

Declares the given expression as a sum

\( (7b-3x)^2 \)

FAQ

Everything you need to know about this question

Why is the first blank 5 and not -5?

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Great question! In (x?)2 (x-?)^2 , the question mark represents the value being subtracted, not a negative number. Since a2=25 a^2 = 25 , we have a=5 a = 5 , making it (x5)2 (x-5)^2 .

How do I find the middle term?

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Use the perfect square formula! For (xa)2 (x-a)^2 , the middle term is always 2ax -2ax . Since a=5 a = 5 , the middle term is 2(5)x=10x -2(5)x = -10x . But the blank asks for the positive coefficient, so it's 10x.

What if the constant term wasn't a perfect square?

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If the constant term isn't a perfect square (like 24 or 30), then you cannot write it as a perfect square trinomial. Perfect squares only work when the constant term equals a2 a^2 for some whole number a a .

Can I check my answer by expanding?

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Absolutely! That's the best way to verify. Expand (x5)2 (x-5)^2 : (x5)(x5)=x25x5x+25=x210x+25 (x-5)(x-5) = x^2 - 5x - 5x + 25 = x^2 - 10x + 25 . This matches the given form perfectly!

Why does the problem show the middle term as positive 10x in the answer?

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The equation format is x2?+25 x^2 - ? + 25 , where the blank represents the coefficient of the middle term. Since the actual middle term is 10x -10x , the coefficient is 10x (the minus sign is already shown).

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