(x+y)2−(x−y)2+(x−y)(x+y)=?
To solve this problem, we'll follow these steps:
- Step 1: Expand (x+y)2
- Step 2: Expand (x−y)2
- Step 3: Rearrange and simplify the entire expression
Now, let's work through each step:
Step 1: We expand (x+y)2 using the formula for the square of a sum:
(x+y)2=x2+2xy+y2.
Step 2: We expand (x−y)2 using the formula for the square of a difference:
(x−y)2=x2−2xy+y2.
Step 3: Substitute these expansions back into the original expression:
(x+y)2−(x−y)2+(x−y)(x+y) becomes:
(x2+2xy+y2)−(x2−2xy+y2)+(x−y)(x+y).
First, simplify (x2+2xy+y2)−(x2−2xy+y2):
– x2+2xy+y2−x2+2xy−y2=4xy.
Next, consider (x−y)(x+y):
By using the identity for difference of squares: (x−y)(x+y)=x2−y2.
Thus, combining our results gives:
4xy+x2−y2=x2+4xy−y2.
Therefore, the solution to the problem is x2+4xy−y2.
x2+4xy−y2