Expand and Simplify: Solving (x+y)²-(x-y)²+(x-y)(x+y)

Question

(x+y)2(xy)2+(xy)(x+y)=? (x+y)^2-(x-y)^2+(x-y)(x+y)=\text{?}

Video Solution

Solution Steps

00:00 Simply
00:03 We'll use shortened multiplication formulas to open all brackets
00:49 We'll reduce what we can
00:56 Negative times positive is always negative
00:59 Negative times negative is always positive
01:12 Let's collect like terms
01:25 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Expand (x+y)2(x+y)^2
  • Step 2: Expand (xy)2(x-y)^2
  • Step 3: Rearrange and simplify the entire expression

Now, let's work through each step:
Step 1: We expand (x+y)2(x+y)^2 using the formula for the square of a sum:
(x+y)2=x2+2xy+y2(x+y)^2 = x^2 + 2xy + y^2.

Step 2: We expand (xy)2(x-y)^2 using the formula for the square of a difference:
(xy)2=x22xy+y2(x-y)^2 = x^2 - 2xy + y^2.

Step 3: Substitute these expansions back into the original expression: (x+y)2(xy)2+(xy)(x+y)(x+y)^2-(x-y)^2+(x-y)(x+y) becomes: (x2+2xy+y2)(x22xy+y2)+(xy)(x+y).(x^2 + 2xy + y^2) - (x^2 - 2xy + y^2) + (x-y)(x+y).

First, simplify (x2+2xy+y2)(x22xy+y2)(x^2 + 2xy + y^2) - (x^2 - 2xy + y^2):
x2+2xy+y2x2+2xyy2=4xy.x^2 + 2xy + y^2 - x^2 + 2xy - y^2 = 4xy.

Next, consider (xy)(x+y)(x-y)(x+y):
By using the identity for difference of squares: (xy)(x+y)=x2y2(x-y)(x+y) = x^2 - y^2.

Thus, combining our results gives:
4xy+x2y2=x2+4xyy2.4xy + x^2 - y^2 = x^2 + 4xy - y^2.

Therefore, the solution to the problem is x2+4xyy2x^2 + 4xy - y^2.

Answer

x2+4xyy2 x^2+4xy-y^2