Determine the Term-to-Term Rule for the Sequence: -1, 3, 7

Arithmetic Sequences with Linear Term Rules

What is the term-to-term rule for the sequence below?

1,3,7 -1,3,7

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the sequence formula
00:04 Identify the first term according to the given data
00:09 Notice the constant difference between terms
00:14 This is the constant difference
00:18 Use the formula to describe an arithmetic sequence
00:22 Substitute appropriate values and solve to find the sequence formula
00:39 Open parentheses properly, multiply by each factor
00:43 Continue solving
00:54 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

What is the term-to-term rule for the sequence below?

1,3,7 -1,3,7

2

Step-by-step solution

To solve this problem, we'll determine the term-to-term rule by identifying if this sequence is arithmetic and calculating the common difference.

  • Step 1: Calculate the common difference dd.
    From the given sequence, compute d=a2a1=3(1)=4d = a_2 - a_1 = 3 - (-1) = 4; similarly, d=a3a2=73=4d = a_3 - a_2 = 7 - 3 = 4.

  • Step 2: Formulate the general term ana_n of the sequence.
    Since the sequence has a common difference of 44, it is an arithmetic sequence. The formula for an arithmetic sequence is given by an=a1+(n1)da_n = a_1 + (n-1)d.

  • Step 3: Substitute the known values and simplify.
    Using a1=1a_1 = -1 and d=4d = 4, the expression becomes an=1+(n1)×4a_n = -1 + (n-1) \times 4 which simplifies to an=1+4n4=4n5a_n = -1 + 4n - 4 = 4n - 5.

  • Step 4: Verify the formula with the given terms.
    Check a1=4×15=1a_1 = 4 \times 1 - 5 = -1; a2=4×25=3a_2 = 4 \times 2 - 5 = 3; a3=4×35=7a_3 = 4 \times 3 - 5 = 7. All match the given sequence.

Therefore, the term-to-term rule for the sequence is 4n5 4n - 5 .

Among the choices provided, the correct option is :

4n5 4n-5

3

Final Answer

4n5 4n-5

Key Points to Remember

Essential concepts to master this topic
  • Common Difference: Calculate d = next term - previous term consistently
  • Formula Method: Use an=a1+(n1)d a_n = a_1 + (n-1)d where a1=1 a_1 = -1 and d=4 d = 4
  • Verification: Check each term: 4(1)5=1 4(1)-5 = -1 , 4(2)5=3 4(2)-5 = 3 , 4(3)5=7 4(3)-5 = 7

Common Mistakes

Avoid these frequent errors
  • Using position-to-term rule instead of finding nth term formula
    Don't just say 'add 4 each time' = incomplete answer! Position-to-term rules tell you how to get the next term, but the question asks for the nth term formula. Always find the general formula an=4n5 a_n = 4n - 5 that works for any position n.

Practice Quiz

Test your knowledge with interactive questions

Look at the following set of numbers and determine if there is any property, if so, what is it?

\( 94,96,98,100,102,104 \)

FAQ

Everything you need to know about this question

What's the difference between term-to-term and position-to-term rules?

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Term-to-term tells you how to get from one term to the next (like 'add 4'). Position-to-term gives you a formula to find any term directly using its position, like an=4n5 a_n = 4n - 5 .

Why do I need to check if the common difference is the same?

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If the differences aren't equal, it's not an arithmetic sequence! You need a consistent pattern to use the arithmetic sequence formula an=a1+(n1)d a_n = a_1 + (n-1)d .

How do I remember which formula to use?

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For arithmetic sequences, always use an=a1+(n1)d a_n = a_1 + (n-1)d . Think: start with first term, then add the common difference (n-1) times to reach position n.

What if I get confused with the algebra in the final step?

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Take it step by step! an=1+(n1)×4 a_n = -1 + (n-1) \times 4 becomes an=1+4n4 a_n = -1 + 4n - 4 , then combine like terms: an=4n5 a_n = 4n - 5 .

Can I use this method for any arithmetic sequence?

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Yes! As long as you have a constant common difference, this formula works. Just substitute your specific values for a1 a_1 and d d .

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