Determine the Term-to-Term Rule for the Sequence: -1, 3, 7

Arithmetic Sequences with Linear Term Rules

What is the term-to-term rule for the sequence below?

1,3,7 -1,3,7

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the sequence formula
00:04 Identify the first term according to the given data
00:09 Notice the constant difference between terms
00:14 This is the constant difference
00:18 Use the formula to describe an arithmetic sequence
00:22 Substitute appropriate values and solve to find the sequence formula
00:39 Open parentheses properly, multiply by each factor
00:43 Continue solving
00:54 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

What is the term-to-term rule for the sequence below?

1,3,7 -1,3,7

2

Step-by-step solution

To solve this problem, we'll determine the term-to-term rule by identifying if this sequence is arithmetic and calculating the common difference.

  • Step 1: Calculate the common difference dd.
    From the given sequence, compute d=a2a1=3(1)=4d = a_2 - a_1 = 3 - (-1) = 4; similarly, d=a3a2=73=4d = a_3 - a_2 = 7 - 3 = 4.

  • Step 2: Formulate the general term ana_n of the sequence.
    Since the sequence has a common difference of 44, it is an arithmetic sequence. The formula for an arithmetic sequence is given by an=a1+(n1)da_n = a_1 + (n-1)d.

  • Step 3: Substitute the known values and simplify.
    Using a1=1a_1 = -1 and d=4d = 4, the expression becomes an=1+(n1)×4a_n = -1 + (n-1) \times 4 which simplifies to an=1+4n4=4n5a_n = -1 + 4n - 4 = 4n - 5.

  • Step 4: Verify the formula with the given terms.
    Check a1=4×15=1a_1 = 4 \times 1 - 5 = -1; a2=4×25=3a_2 = 4 \times 2 - 5 = 3; a3=4×35=7a_3 = 4 \times 3 - 5 = 7. All match the given sequence.

Therefore, the term-to-term rule for the sequence is 4n5 4n - 5 .

Among the choices provided, the correct option is :

4n5 4n-5

3

Final Answer

4n5 4n-5

Key Points to Remember

Essential concepts to master this topic
  • Common Difference: Calculate d = next term - previous term consistently
  • Formula Method: Use an=a1+(n1)d a_n = a_1 + (n-1)d where a1=1 a_1 = -1 and d=4 d = 4
  • Verification: Check each term: 4(1)5=1 4(1)-5 = -1 , 4(2)5=3 4(2)-5 = 3 , 4(3)5=7 4(3)-5 = 7

Common Mistakes

Avoid these frequent errors
  • Using position-to-term rule instead of finding nth term formula
    Don't just say 'add 4 each time' = incomplete answer! Position-to-term rules tell you how to get the next term, but the question asks for the nth term formula. Always find the general formula an=4n5 a_n = 4n - 5 that works for any position n.

Practice Quiz

Test your knowledge with interactive questions

12 ☐ 10 ☐ 8 7 6 5 4 3 2 1

Which numbers are missing from the sequence so that the sequence has a term-to-term rule?

FAQ

Everything you need to know about this question

What's the difference between term-to-term and position-to-term rules?

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Term-to-term tells you how to get from one term to the next (like 'add 4'). Position-to-term gives you a formula to find any term directly using its position, like an=4n5 a_n = 4n - 5 .

Why do I need to check if the common difference is the same?

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If the differences aren't equal, it's not an arithmetic sequence! You need a consistent pattern to use the arithmetic sequence formula an=a1+(n1)d a_n = a_1 + (n-1)d .

How do I remember which formula to use?

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For arithmetic sequences, always use an=a1+(n1)d a_n = a_1 + (n-1)d . Think: start with first term, then add the common difference (n-1) times to reach position n.

What if I get confused with the algebra in the final step?

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Take it step by step! an=1+(n1)×4 a_n = -1 + (n-1) \times 4 becomes an=1+4n4 a_n = -1 + 4n - 4 , then combine like terms: an=4n5 a_n = 4n - 5 .

Can I use this method for any arithmetic sequence?

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Yes! As long as you have a constant common difference, this formula works. Just substitute your specific values for a1 a_1 and d d .

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