Based on the data in the diagram, find for which X values the graph of the function
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Based on the data in the diagram, find for which X values the graph of the function
First, we examine the provided graph of the quadratic function . The graph clearly shows the x-intercepts (where the function crosses the x-axis) at and .
Since the quadratic function appears to be a standard parabola opening upwards, the portion of the graph between these two x-intercepts will be above the x-axis, which means that in this interval.
The intervals to the left of and to the right of will be where the graph lies below the x-axis, meaning in those regions.
Thus, the graph shows that the function is positive between and . Therefore, the solution to the problem is:
The graph of the function below intersects the X-axis at points A and B.
The vertex of the parabola is marked at point C.
Find all values of \( x \) where \( f\left(x\right) > 0 \).
Look at the y-values! When the graph is above the x-axis, f(x) > 0 (positive). When it's below the x-axis, f(x) < 0 (negative). The x-axis is where f(x) = 0.
If the parabola opened downward, it would be positive between the x-intercepts and negative outside them - exactly the opposite! Always check which direction the parabola opens.
No! At x = -3 and x = 3, the function equals zero, not positive. Since we want f(x) > 0 (strictly greater), we use , not ≤.
The smooth, U-shaped curve with exactly two x-intercepts is the classic shape of a quadratic function (parabola). It has a lowest point (vertex) and extends infinitely upward on both sides.
Look for the points where the curve crosses the x-axis - these are clearly marked as -3 and 3 in this graph. The function changes from negative to positive (or vice versa) at these crossing points.
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