Discover the Symmetrical Axis in -3x^2 + 3: A Quadratic Analysis

Question

Given the expression of the quadratic function

The symmetrical axis of the expression must be found.

$f(x)=-3x^2+3$

00:00 Find the axis of symmetry for the function

00:03 The axis of symmetry is the X value at the vertex point

00:06 The point where if you fold the parabola in half, both halves are identical

00:09 Let's look at the function's coefficients

00:21 We'll use the formula to calculate the vertex point

00:32 We'll substitute appropriate values according to the given data and solve for X at the point

00:43 And this is the solution to the question

To find the axis of symmetry for the quadratic function $f(x) = -3x^2 + 3$ , we follow these steps:

Identify coefficients: Here, $a = -3$ , $b = 0$ , and $c = 3$ .
Use the axis of symmetry formula for a quadratic $ax^2 + bx + c$ given by $x = -\frac{b}{2a}$ .
Substitute $b = 0$ and $a = -3$ into the formula: $x = -\frac{0}{2 \times (-3)}$ .
This simplifies to $x = 0$ .

The axis of symmetry for the quadratic function $f(x) = -3x^2 + 3$ is therefore $x = 0$ .

$x=0$