Identify the Symmetrical Axis in the Quadratic: 2x^2 + 8x + 4

Question

Given the expression of the quadratic function

The symmetrical axis of the expression must be found.

f(x)=2x2+8x+4 f(x)=2x^2+8x+4

Video Solution

Solution Steps

00:00 Find the axis of symmetry for the function
00:03 The axis of symmetry is the X value at the vertex point
00:06 The point where if you fold the parabola in half, both halves are identical
00:10 Let's examine the function's coefficients
00:24 We'll use the formula to calculate the vertex point
00:30 We'll substitute appropriate values according to the given data and solve for X at the point
00:41 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we'll apply the formula for the axis of symmetry of a quadratic function:

  • Step 1: Recognize the function is f(x)=2x2+8x+4 f(x) = 2x^2 + 8x + 4 .
  • Step 2: Identify the coefficients: a=2 a = 2 and b=8 b = 8 .
  • Step 3: Use the axis of symmetry formula x=b2a x = -\frac{b}{2a} .

Now, substituting the values of a a and b b into the formula:
x=82×2 x = -\frac{8}{2 \times 2} ,
x=84 x = -\frac{8}{4} ,
x=2 x = -2 .

Therefore, the axis of symmetry for the given quadratic function is x=2 x = -2 .

Answer

x=2 x=-2