Divisibility Test: Is 564 Divisible by 3?

Divisibility Rules with Digit Sum Method

Determine if the following number is divisible by 3:

564 564

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Determine if the number is divisible by 3
00:04 A number is divisible by 3 only if the sum of its digits is divisible by 3
00:08 Let's sum its digits and divide by 3
00:12 The sum of digits is divisible by 3, therefore the number is divisible by 3
00:16 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Determine if the following number is divisible by 3:

564 564

2

Step-by-step solution

To determine if the number 564 is divisible by 3, we apply the divisibility rule for 3:

  • A number is divisible by 3 if the sum of its digits is divisible by 3.

Let's calculate the sum of the digits of 564:

5+6+4=15 5 + 6 + 4 = 15

Next, we check if 15 is divisible by 3. Since 15 can be divided by 3 without a remainder, it is divisible by 3:

15÷3=5 15 \div 3 = 5

Therefore, based on the divisibility rule, 564 is divisible by 3.

Thus, the correct answer is Yes.

3

Final Answer

Yes

Key Points to Remember

Essential concepts to master this topic
  • Rule: A number divides by 3 if digit sum divides by 3
  • Technique: Add digits: 5+6+4=15 5 + 6 + 4 = 15 , then check if 15 ÷ 3 works
  • Check: Verify 564 ÷ 3 = 188 with no remainder confirms our digit sum test ✓

Common Mistakes

Avoid these frequent errors
  • Checking if the last digit is divisible by 3
    Don't just look at the last digit (4) and think 564 isn't divisible by 3 = wrong answer! The last digit rule only works for 2, 5, and 10. Always add ALL digits together for the divisibility by 3 test.

Practice Quiz

Test your knowledge with interactive questions

Will a number divisible by 6 necessarily be divisible by 3?

FAQ

Everything you need to know about this question

Why does adding digits work for divisibility by 3?

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This works because of how our base-10 number system interacts with multiples of 3. The mathematical proof involves modular arithmetic, but the rule always works reliably!

What if the digit sum is still a large number?

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Keep adding! For example, if digits sum to 27, add again: 2+7=9 2 + 7 = 9 . Since 9 is divisible by 3, so is the original number. Keep going until you get a single digit.

Does this work for divisibility by 9 too?

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Yes! The digit sum rule works for both 3 and 9. If the digit sum is divisible by 9, then the original number is divisible by 9 (and automatically by 3 too).

Can I use this shortcut on tests?

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Absolutely! The digit sum test is faster than long division and is a standard mathematical method. Teachers expect you to know and use divisibility rules efficiently.

What if I make an addition error with the digits?

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Double-check your digit addition! Write it out clearly: 5+6=11 5 + 6 = 11 , then 11+4=15 11 + 4 = 15 . Small arithmetic errors will give you the wrong answer.

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