Evaluate 2(2n-2): Finding the Position of 20 in the Sequence

Sequence Formulas with Position Finding

Given a formula with a constant property that depends onn n :

2(2n2) 2(2n-2)

Is the number 20 Is it part of the series? If so, what element is it in the series?

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:11 Is the number 20 part of our sequence, and if it is, what position does it hold?
00:17 To find out, let's insert 20 into the sequence formula and see what happens.
00:22 If our answer for N is both positive and a whole number, that means 20 is a term and N is its position.
00:29 Let's simplify the equation as much as we can.
00:33 Next, we'll isolate the variable N in our equation.
00:50 And that's how we figure out if 20 is in the sequence!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Given a formula with a constant property that depends onn n :

2(2n2) 2(2n-2)

Is the number 20 Is it part of the series? If so, what element is it in the series?

2

Step-by-step solution

To determine if the number 20 is part of the sequence given by the formula 2(2n2)2(2n-2), we proceed as follows:

  • Step 1: Set up the equation, 2(2n2)=202(2n-2) = 20.
  • Step 2: Simplify the equation:
    2(2n2)=4n42(2n-2) = 4n - 4, thus we have 4n4=204n - 4 = 20.
  • Step 3: Solve for nn:
    Add 4 to both sides: 4n4+4=20+44n - 4 + 4 = 20 + 4 gives 4n=244n = 24.
    Divide both sides by 4: n=244=6n = \frac{24}{4} = 6.
  • Step 4: Check if nn is a positive integer.
    n=6n = 6 is indeed a positive integer.

Since n=6n = 6 is a positive integer, 20 is indeed part of the sequence, and it is the 6th term.

Therefore, the solution to the problem is Yes, 6.

3

Final Answer

Yes, 6 6

Key Points to Remember

Essential concepts to master this topic
  • Formula Setup: Set expression equal to given value to find position
  • Algebraic Solution: Solve 2(2n2)=20 2(2n-2) = 20 gives n=6 n = 6
  • Verification: Substitute back: 2(262)=2(10)=20 2(2 \cdot 6 - 2) = 2(10) = 20

Common Mistakes

Avoid these frequent errors
  • Forgetting to check if n is a positive integer
    Don't assume any solution works in sequences = wrong position identification! Sequences only use positive whole numbers for positions. Always verify that your calculated n-value is a positive integer before concluding the term exists.

Practice Quiz

Test your knowledge with interactive questions

12 ☐ 10 ☐ 8 7 6 5 4 3 2 1

Which numbers are missing from the sequence so that the sequence has a term-to-term rule?

FAQ

Everything you need to know about this question

What does it mean for a number to be 'part of the sequence'?

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A number is part of the sequence if you can find a positive integer value of n that makes the formula equal that number. If n isn't a positive integer, the number doesn't appear in the sequence.

Why do we need n to be positive?

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Sequence positions start at n = 1, 2, 3... because you can't have a 0th term or negative position! If you get n = 0 or negative, that number isn't in the sequence.

What if I get a decimal or fraction for n?

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If n is not a whole number, then that target value doesn't appear in the sequence. Positions must be counting numbers: 1st term, 2nd term, 3rd term, etc.

How do I solve 2(2n-2) = 20 step by step?

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Step 1: Distribute: 4n4=20 4n - 4 = 20
Step 2: Add 4: 4n=24 4n = 24
Step 3: Divide by 4: n=6 n = 6

Should I always check my answer?

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Absolutely! Substitute your n-value back into the original formula. If you get the target number, you're correct. For this problem: 2(262)=2(10)=20 2(2 \cdot 6 - 2) = 2(10) = 20

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