Evaluate (4^5)^2: Solving Double Exponent Expression

Power of a Power with Integer Exponents

Insert the corresponding expression:

(45)2= \left(4^5\right)^2=

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1

Understand the problem

Insert the corresponding expression:

(45)2= \left(4^5\right)^2=

2

Step-by-step solution

To solve this problem, let's carefully follow these steps:

  • Step 1: Identify the base and exponents in the expression.
  • Step 2: Use the power of a power rule to simplify the expression.
  • Step 3: Choose the appropriate option from the given answer choices.

Now, let's break this down:

Step 1: The expression given is (45)2(4^5)^2. Here, the base is 4, the inner exponent is 5, and the outer exponent is 2.

Step 2: We apply the power of a power rule for exponents, which states that (am)n=amn(a^m)^n = a^{m \cdot n}.

Using the rule, we have:

(45)2=452=410 (4^5)^2 = 4^{5 \cdot 2} = 4^{10}

This means the expression (45)2(4^5)^2 can be simplified to 4104^{10}.

Step 3: From the answer choices provided, we need to select the one corresponding to 4524^{5 \cdot 2}:

  • Choice 1: 4254^{\frac{2}{5}} - This is incorrect because it deals with division of exponents and not multiplication.
  • Choice 2: 4524^{5-2} - This is incorrect as it incorrectly subtracts the exponents.
  • Choice 3: 45×24^{5 \times 2} - This is the correct choice.
  • Choice 4: 45+24^{5+2} - This is incorrect as it incorrectly adds the exponents.

Therefore, the solution to the problem is 45×2=4104^{5 \times 2} = 4^{10}, which corresponds to choice 3.

3

Final Answer

45×2 4^{5\times2}

Key Points to Remember

Essential concepts to master this topic
  • Power Rule: When raising a power to another power, multiply the exponents
  • Technique: For (45)2(4^5)^2, multiply 5 × 2 to get 4104^{10}
  • Check: Verify that (45)2=45×2=410(4^5)^2 = 4^{5 \times 2} = 4^{10}

Common Mistakes

Avoid these frequent errors
  • Adding or subtracting exponents instead of multiplying
    Don't write (45)2=45+2=47(4^5)^2 = 4^{5+2} = 4^7 or 452=434^{5-2} = 4^3! Adding gives you a much smaller number than the correct answer. Always multiply the exponents when you have a power raised to a power.

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why do we multiply the exponents instead of adding them?

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The power of a power rule says (am)n=am×n(a^m)^n = a^{m \times n}. Think of it this way: (45)2(4^5)^2 means you're multiplying 454^5 by itself, which gives you 10 factors of 4 total!

What's the difference between this and multiplying powers with the same base?

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Great question! When you multiply 45×424^5 \times 4^2, you add the exponents: 45+2=474^{5+2} = 4^7. But when you have (45)2(4^5)^2, you multiply the exponents: 45×2=4104^{5 \times 2} = 4^{10}.

How can I remember which operation to use?

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Look for parentheses! If you see (am)n(a^m)^n with parentheses, multiply the exponents. If you see am×ana^m \times a^n without parentheses around the first power, add the exponents.

What if I have negative exponents?

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The same rule applies! For example, (43)2=43×2=46(4^{-3})^2 = 4^{-3 \times 2} = 4^{-6}. Just multiply the exponents as usual, keeping track of positive and negative signs.

Can I work this out by calculating the numbers first?

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You could calculate 45=10244^5 = 1024, then 102421024^2, but that's much harder! Using the exponent rule (45)2=410(4^5)^2 = 4^{10} is much faster and less error-prone.

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