Evaluate (5×2×6×3)^7: Product and Power Expression

Power of Products with Multiple Factors

Insert the corresponding expression:

(5×2×6×3)7= \left(5\times2\times6\times3\right)^7=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simplify the following problem
00:04 According to the laws of exponents, a product raised to a power (N)
00:10 equals a product where each factor is raised to the same power (N)
00:15 This formula is valid regardless of how many factors are in the product
00:21 We will apply this formula to our exercise
00:26 We will break down the product into each factor separately raised to the power (N)
00:34 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Insert the corresponding expression:

(5×2×6×3)7= \left(5\times2\times6\times3\right)^7=

2

Step-by-step solution

To solve this problem, we'll convert the given product inside the parentheses, (5×2×6×3)7 \left(5 \times 2 \times 6 \times 3\right)^7 , into an expression applying the power of a product rule.

First, recognize that we can apply the rule of exponents as follows:

  • The power of a product rule states (a×b)n=an×bn (a \times b)^n = a^n \times b^n .

Applying this to our variables, we have:

  • (5×2×6×3)7=(5)7×(2)7×(6)7×(3)7 \left(5 \times 2 \times 6 \times 3\right)^7 = (5)^7 \times (2)^7 \times (6)^7 \times (3)^7

Therefore, the expression evaluates to:

57×27×67×37 5^7 \times 2^7 \times 6^7 \times 3^7

3

Final Answer

57×27×67×37 5^7\times2^7\times6^7\times3^7

Key Points to Remember

Essential concepts to master this topic
  • Power Rule: Distribute exponent to each factor in the product
  • Technique: (a×b)n=an×bn (a \times b)^n = a^n \times b^n for all factors
  • Check: Count factors inside and outside: 4 factors become 4 separate powers ✓

Common Mistakes

Avoid these frequent errors
  • Only applying the exponent to some factors
    Don't raise just some factors to the 7th power like 57×2×67×3 5^7 \times 2 \times 6^7 \times 3 = wrong distribution! The power rule requires the exponent to apply to every single factor inside the parentheses. Always distribute the exponent to each and every factor: 57×27×67×37 5^7 \times 2^7 \times 6^7 \times 3^7 .

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why can't I just multiply the numbers first and then raise to the 7th power?

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You absolutely can do that! 5×2×6×3=180 5 \times 2 \times 6 \times 3 = 180 , so 1807 180^7 gives the same result. However, the question asks for the expression form, not the numerical calculation.

How do I remember to apply the exponent to every factor?

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Think of the exponent as a multiplier that affects everything inside the parentheses equally. Just like distributing multiplication, you must distribute the power to each factor: no exceptions!

What if some factors are the same number?

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Each factor gets its own power regardless! For example, (2×2×3)4=24×24×34 (2 \times 2 \times 3)^4 = 2^4 \times 2^4 \times 3^4 . You can combine same bases later using 24×24=28 2^4 \times 2^4 = 2^8 .

Does the order of factors matter when applying the power rule?

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No! Multiplication is commutative, so 57×27×67×37 5^7 \times 2^7 \times 6^7 \times 3^7 equals 27×37×57×67 2^7 \times 3^7 \times 5^7 \times 6^7 . The important thing is that every factor gets the exponent.

Can I group some factors together before applying the power?

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Yes! You could write (5×3)7×(2×6)7=157×127 (5 \times 3)^7 \times (2 \times 6)^7 = 15^7 \times 12^7 , but the question specifically wants each individual factor raised to the 7th power.

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