Calculate (9×7×6×2)^6: Complex Product Exponentiation

Power of Products with Multiple Factors

Insert the corresponding expression:

(9×7×6×2)6= \left(9\times7\times6\times2\right)^6=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simplify the following problem
00:04 According to the laws of exponents, a product raised to a power (N)
00:09 equals a product where each factor is raised to that same power (N)
00:16 This formula is valid regardless of how many factors are in the product
00:20 We will apply this formula to our exercise
00:25 We will break down the product into each factor separately raised to the power (N)
00:35 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Insert the corresponding expression:

(9×7×6×2)6= \left(9\times7\times6\times2\right)^6=

2

Step-by-step solution

Let's solve the problem by using the power of a product rule:

  • The given expression is (9×7×6×2)6(9 \times 7 \times 6 \times 2)^6.
  • According to the rule (a×b×c)n=an×bn×cn(a \times b \times c)^n = a^n \times b^n \times c^n, we need to distribute the power of 6 to each element in the product inside the brackets.
  • Apply the rule: (9×7×6×2)6=96×76×66×26(9 \times 7 \times 6 \times 2)^6 = 9^6 \times 7^6 \times 6^6 \times 2^6.

Therefore, the expression simplifies to 96×76×66×26 9^6 \times 7^6 \times 6^6 \times 2^6 .

3

Final Answer

96×76×66×26 9^6\times7^6\times6^6\times2^6

Key Points to Remember

Essential concepts to master this topic
  • Rule: Distribute exponent to each factor in the product
  • Technique: (a×b×c)n=an×bn×cn (a \times b \times c)^n = a^n \times b^n \times c^n
  • Check: Count factors: 4 in product = 4 terms in final answer ✓

Common Mistakes

Avoid these frequent errors
  • Only applying the exponent to one factor
    Don't just raise 9 to the 6th power and leave the rest = 96×7×6×2 9^6 \times 7 \times 6 \times 2 ! This ignores the distributive property of exponents. Always apply the exponent to every single factor in the product.

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why can't I just calculate the product first, then raise it to the 6th power?

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You could do that, but it's much harder! 9×7×6×2=756 9 \times 7 \times 6 \times 2 = 756 , so you'd need to calculate 7566 756^6 - that's a huge number! Using the power rule keeps numbers manageable.

Do I multiply the exponents when I see (abc)6 (abc)^6 ?

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No! You don't multiply exponents here. The rule is distribute the exponent: each factor gets raised to the 6th power separately, then you multiply the results.

What if some factors are the same, like (6×6×2)3 (6 \times 6 \times 2)^3 ?

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The rule still applies! You'd get 63×63×23 6^3 \times 6^3 \times 2^3 . You could then simplify to 66×23 6^6 \times 2^3 using the rule am×an=am+n a^m \times a^n = a^{m+n} .

How do I remember which rule to use?

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Look for parentheses with multiplication inside and an exponent outside. That's your cue to use the power of a product rule: distribute that outside exponent to each factor inside!

Can I use this rule with variables too?

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Absolutely! (2xy)4=24×x4×y4=16x4y4 (2xy)^4 = 2^4 \times x^4 \times y^4 = 16x^4y^4 . The rule works the same way whether you have numbers, variables, or both.

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