Evaluate the Expression: 2² × 1¹⁰ + 3

0:22×110+3= 0:2^2\times1^{10}+3=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:07 Let's solve this problem step by step.
00:12 First, let's calculate what happens when we use powers.
00:32 Remember, one to the power of any number is always one!
00:39 Zero divided by any number is always zero.
00:46 And zero multiplied by any number, is also zero.
00:50 Great work! And that's how we solve these problems.

Step-by-step written solution

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1

Understand the problem

0:22×110+3= 0:2^2\times1^{10}+3=

2

Step-by-step solution

To solve the expression, we need to follow the order of operations, often remembered by the acronym PEMDAS, which stands for Parentheses, Exponents, Multiplication and Division (left-to-right), Addition and Subtraction (left-to-right).

  • Step 1: Handle the exponentiation in the expression.
    The exponentiation operation is on the number 2, so we compute 22 2^2 which is equal to 4.
  • Step 2: Handle the multiplication.
    We multiply the result of the exponentiation by the number following it. Therefore, we have 4×110 4 \times 1^{10} . Since 110=1 1^{10} = 1 , the expression becomes 4×1=4 4 \times 1 = 4 .
  • Step 3: Handle the operations on either side of multiplication.
    Before evaluating, it's essential to note that the original expression is slightly misunderstood due to potential formatting errors. Let's assume it was meant to use division as 0÷22 0 \div 2^2 due to the notation 0:22 0:2^2 . Therefore, calculate 0÷4 0 \div 4 which is equal to 0.
  • Step 4: Handle the addition.
    Finally, we add 3 to the result of the division: 0+3=3 0 + 3 = 3 .

Thus, the final answer is 3.

3

Final Answer

3

Practice Quiz

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What is the result of the following equation?

\( 36-4\div2 \)

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