Expand and Simplify: (3y+4a)² - 9(y-2a)(y+2a)

Question

(3y+4a)29(y2a)(y+2a)=? (3y+4a)^2-9(y-2a)(y+2a)=\text{?}

Video Solution

Solution Steps

00:00 Simply
00:08 We'll use the shortened multiplication formulas to open the parentheses
00:39 We'll square each factor in the multiplication
01:07 We'll properly open parentheses and multiply by each factor
01:16 We'll group the terms
01:37 We'll factor each multiplication with factor 4
01:45 We'll find the common factor and take it out of parentheses
01:59 And this is the solution to the question

Step-by-Step Solution

To solve the problem, we will follow these steps:

  • Step 1: Expand the square of the binomial (3y+4a)(3y + 4a).
  • Step 2: Simplify the product of the binomials 9(y2a)(y+2a)9(y-2a)(y+2a).
  • Step 3: Subtract the second result from the first and simplify.

Let's work through each step:
Step 1: The expression (3y+4a)2(3y + 4a)^2 can be expanded as follows:

(3y+4a)2=(3y)2+2(3y)(4a)+(4a)2=9y2+24ay+16a2(3y + 4a)^2 = (3y)^2 + 2(3y)(4a) + (4a)^2 = 9y^2 + 24ay + 16a^2.

Step 2: Simplify the expression 9(y2a)(y+2a)9(y-2a)(y+2a). This uses the difference of squares formula where (y2a)(y+2a)=y2(2a)2(y-2a)(y+2a) = y^2 - (2a)^2:

(y2a)(y+2a)=y24a2(y-2a)(y+2a) = y^2 - 4a^2.

Then multiply by 9:

9(y24a2)=9y236a29(y^2 - 4a^2) = 9y^2 - 36a^2.

Step 3: Now subtract the second result from the first:

(9y2+24ay+16a2)(9y236a2)=9y2+24ay+16a29y2+36a2(9y^2 + 24ay + 16a^2) - (9y^2 - 36a^2) = 9y^2 + 24ay + 16a^2 - 9y^2 + 36a^2.

Combine and simplify:

24ay+52a224ay + 52a^2.

Factoring out 4a4a from the expression:

4a(6y+13a)4a(6y + 13a).

Therefore, the solution to the problem is: 4a(6y+13a)4a(6y + 13a).

Answer

4a(6y+13a) 4a(6y+13a)