(3y+4a)2−9(y−2a)(y+2a)=?
To solve the problem, we will follow these steps:
- Step 1: Expand the square of the binomial (3y+4a).
- Step 2: Simplify the product of the binomials 9(y−2a)(y+2a).
- Step 3: Subtract the second result from the first and simplify.
Let's work through each step:
Step 1: The expression (3y+4a)2 can be expanded as follows:
(3y+4a)2=(3y)2+2(3y)(4a)+(4a)2=9y2+24ay+16a2.
Step 2: Simplify the expression 9(y−2a)(y+2a). This uses the difference of squares formula where (y−2a)(y+2a)=y2−(2a)2:
(y−2a)(y+2a)=y2−4a2.
Then multiply by 9:
9(y2−4a2)=9y2−36a2.
Step 3: Now subtract the second result from the first:
(9y2+24ay+16a2)−(9y2−36a2)=9y2+24ay+16a2−9y2+36a2.
Combine and simplify:
24ay+52a2.
Factoring out 4a from the expression:
4a(6y+13a).
Therefore, the solution to the problem is: 4a(6y+13a).
4a(6y+13a)